Answer:
3.7 m/s
Explanation:
M = 444 kg
U = 5 m/s
m = 344 kg
u = - 5 m/s
Let the velocity of train is V and the car s v after the collision.
As the collision is elastic
By use of conservation of momentum
MU + mu = MV + mv
444 x 5 - 344 x 5 = 444 V + 344 v
500 = 444 V + 344 v
125 = 111 V + 86 v .... (1)
By using the formula of coefficient of restitution ( e = 1 for elastic collision)

-5 - 5 = V - v
V - v = - 10
v = V + 10
Substitute the value of v in equation (1)
125 = 111 V + 86 (V + 10)
125 = 197 V + 860
197 V = - 735
V = - 3.7 m/s
Thus, the speed of first car after collision is 3.7 m/s. negative sign shows that the direction is reverse as before the collision.
Answer:
muddy water is a heterogeneous mixture, which is Suspension.
Answer:
The SI units of the “A” is m (meters)
The SI units of the “B” is m/s^2
Explanation:
Given the distance = d meters.
Time taken to travel = t (seconds)
Function of the distance, d = A + Bt^2
Now we have given the above information and from the given distance function, we have to find the SI units of the A and B. Here, below are the SI units.
Thus, the SI units of the “A” is = m (meters)
The SI units of the “B” is = m/s^2
(vx)f=(vx)i + a(t)
since it starts from rest the initial velocity is zero so you can do some algebra and get your (a).
The time when the cheetah catches up with the widebeest is 1.53 s
If the initial separation distance approaches zero, it will take the cheetah 1.05 s to catch the widebeest.
The given parameters;
- speed of the wildebeest calf, Vw = 10 m/s
- distance traveled by the calf before the cheetah stands up = 7 m
- constant acceleration of the cheetah, a = 9.5 m/s²
Let the speed of the cheetah = Vc
let the time the cheetah catches up with the wildebeest = t


Apply relative velocity formula to determine the time when the cheetah catches up with the widebeest;
Assuming the wildebeest and the cheetah are running in the same direction;

The time when the cheetah catches up with the widebeest is 1.53 s
If the initial separation distance approaches zero;

Thus, if the initial separation distance approaches zero, it will take the cheetah 1.05 s to catch the widebeest.
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