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ValentinkaMS [17]
3 years ago
7

How many grams of NaOH are needed to make 500 mL of a 2.5 M NaOH solution

Chemistry
1 answer:
Veronika [31]3 years ago
4 0
The number of grams  of NaOH  that are needed to make 500 ml of 2.5 M NaOH solution

calculate the number of moles =molarity x volume/1000

= 2.5 x 500/1000 = 1.25 moles

mass = moles  x molar mass of NaOH

= 1.25 x40= 50 grams of NaOH
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Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
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Answer:

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Explanation:

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from the above balanced equaion;

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but we have 0.16 mole so oxygen will be the limiting reagent and sulpher will be the excess reagent

so product will depend on the limiting reagent

from the balance equation

3 mole of sulpher gives 2 mole SO_3

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and

actual production of SO_3 =7.9gram

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\%\, yield\, \, SO_3=\frac{7.9}{9.6} \times 100=82.29

\%\, yield\, \, SO_3=82.29

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