<h3>
Answer:</h3>
132.03 g
<h3>
Explanation:</h3>
<u>We are given;</u>
- The equation for the reaction as;
Fe₂O₃ + 3CO → 2Fe + 3CO₂
- Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
- Mass of CO as 84 grams
We are required to calculate the mass of CO₂ that will produced.
<h3>Step 1: Calculate the number of moles of CO</h3>
Moles = Mass ÷ Molar mass
Molar mass of CO = 28.01 g/mol
Therefore;
Moles of CO = 84 g ÷ 28.01 g/mol
= 2.9989 moles
= 3.0 moles
<h3>Step 2: Calculate the number of moles of CO₂</h3>
- From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
- Therefore; the mole ratio of CO to CO₂ is 1 : 1
- Hence; Moles of CO = Moles of CO₂
Moles of CO₂ = 3.0 Moles
But; mass = Moles × molar mass
Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol
= 132.03 g
Hence, the mass of CO₂ produced from the reaction is 132.03 g
Answer:
C.5
Explanation:
A number of electrons present in valence shell of penultimate Shell represents the group of elements.
For s block elements: no.of group=number of valence shell electron.
p block elements: no. of group= 2 + 10 + number of valence electrons.
d block elements: no. of group= number(n-1)d electrons + number of electrons in nth shell.
Here, the differential electron is in p orbital hence, it belongs to p block
No. of group= 2+ 10 + 3=15 i.e 15th group or VA group.
Answer: wait im gonna search some info.
Explanation:I come back with an asnwer for you
Use the formula:
P1V1/T1N1 = P2V2/T2N2
You can cross out T1,N1,T2, and N2 because you are working with pressure and volume in this equation.
Now, you are left with Boyle’s Law:
P1V1 = P2V2
Substitute the values in
STP = 1 atm for pressure
(1 atm)(2.1L) = P2 (0.125 L) [I converted 125 ml to liters so they would be the same unit]
Now, divide both sides by 0.125 to find P2
P2 = (1 atm)(2.1 L)/(0.125 L)
Liters cancel out
P2 = 16.8 atm
Sorry i need the points but if i knew the answer i’ll tell you sorry
