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wel
2 years ago
10

A 66.0 kg diver is 2.30 m above the water, falling at speed of 2.20 m/s. Calculate her kinetic energy as she hits the water. (Ne

glect air friction)
Physics
1 answer:
fenix001 [56]2 years ago
6 0

The kinetic energy of the diver as she hits the water is 159.72J. Details about kinetic energy can be found below.

<h3>How to calculate kinetic energy?</h3>

The kinetic energy of a body can be calculated using the following formula:

K.E = ½ × m × v²

Where;

  • K.E = kinetic energy
  • m = mass
  • v = velocity

According to this question, a 66.0 kg diver is 2.30 m above the water and falls at speed of 2.20 m/s.

Kinetic energy = ½ × 66 × 2.2²

K.E = 159.72J

Therefore, the kinetic energy of the diver as she hits the water is 159.72J.

Learn more about kinetic energy at: brainly.com/question/12669551

#SPJ1

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14523.55J

Explanation:

The work done by the jogger against gravity is given by the following equation;

W=mgh.................(1)

where m is the mass, g is acceleration due to gravity taken as 9.8m/s^2 and h is the height of the hill.

Since the length of the hill is 132m and it is inclined at 12 degrees to the horizontal, the height is thus given as follows;

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Substituting this into equation (1) with all other necessary parameters, we obtain the following;

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In a ruby laser, an electron jumps from a higher energy level to a lower one. if the energy difference between the two levels is
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<h3>How can we calculate the wavelength of the emitted photon?</h3>

To calculate the wavelength of the photon we are using the formula,

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Or,\lambda= \frac{h\times c}{\triangle E}

We are given here,

\triangle E= The energy difference between the two levels = 1. 8 ev= 1.8\times 1.6 \times 10^{-19} C.

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We have to find the wavelength of the emitted photon =\lambda m.

Therefore, we substitute the known parameters in the above equation, we can find that,

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Or,\lambda= \frac{6.626\times 10^{-34}\times 3\times 10^8}{1.8\times 1.6 \times 10^{-19}}

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From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.

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brainly.com/question/17245697

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