Explanation:
It is given that,
Density of asteroid, 
Mass of asteroid, 
We need to find the diameter of the asteroid. The formula of density is given by:

V is the volume of spherical shaped asteroid, 



r = 2441311.12 m
Diameter = 2 × radius
d = 4882622.24 m
or

Hence, this is the required solution.
Answer:
a) k = 2231.40 N/m
b) v = 0.491 m/s
Explanation:
Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.
when the box encounters the spring, all the energy of the box is kinetic energy:
the energy relationship between the box and the spring is given by:
1/2(m)×(v^2) = 1/2(k)×(x^2)
(m)×(v^2) = (k)×(x^2)
a) (m)×(v^2) = (k)×(x^2)
k = [(m)×(v^2)]/(x^2)
k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)
k = 2231.40 N/m
Therefore, the force spring constant is 2231.40 N/m
b) (m)×(v^2) = (k)×(x^2)
v^2 = [(k)(x^2)]/m
v = \sqrt{ [(k)(x^2)]/m}
v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}
= 0.491 m/s
uhhhh idk cheif...
thats a big oof right there.
ged is always an option
(a) 
The moment of inertia of a uniform-density disk is given by

where
M is the mass of the disk
R is its radius
In this problem,
M = 16 kg is the mass of the disk
R = 0.19 m is the radius
Substituting into the equation, we find

(b) 142.5 J
The rotational kinetic energy of the disk is given by

where
I is the moment of inertia
is the angular velocity
We know that the disk makes one complete rotation in T=0.2 s (so, this is the period). Therefore, its angular velocity is

And so, the rotational kinetic energy is

(c) 
The rotational angular momentum of the disk is given by

where
I is the moment of inertia
is the angular velocity
Substituting the values found in the previous parts of the problem, we find

Uh it’s D i’m pretty sure