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kotykmax [81]
3 years ago
12

A particular molecule has a small molecular mass of approximately 1000 daltons. What should be done to make this molecule more a

ntigenic?
Physics
1 answer:
barxatty [35]3 years ago
7 0

Answer:

Bind it to a large protein

Explanation:

An antigen is a molecule that binds to Ag-specific receptors, but cannot necessarily induce an immune response in the body by itself. Antigens are proteins , peptides (amino acid chains) and

polysaccharides (chains of monosaccharides/simple sugars) but

lipids and nucleic acids become antigens only when combined with proteins and polysaccharides. [4] In general, saccharides and lipids (as opposed to peptides) qualify as antigens but not as immunogens since they cannot elicit an immune response on their own. Furthermore, for a peptide to induce an immune response it must be a large enough size, thus binding to proteins

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Assuming a roughly spherical shape and a density of 4000 kg/m3, estimate the diameter of an asteroid having the average mass of
vredina [299]

Explanation:

It is given that,

Density of asteroid, \rho=4000\ kg/m^3

Mass of asteroid, m=10^{17}\ kg

We need to find the diameter of the asteroid. The formula of density is given by:

\rho=\dfrac{m}{V}

V is the volume of spherical shaped asteroid, V=\dfrac{4}{3}\pi r^3

r^3=\dfrac{3M}{4\pi \rho}

r^3=\dfrac{3\times 10^{17}\ kg}{4\pi \times 4000\ kg/m^3}

r^3=\sqrt{5.96\times 10^{12}}

r = 2441311.12 m

Diameter = 2 × radius

d = 4882622.24 m

or

d=4.88\times 10^6\ m

Hence, this is the required solution.

8 0
3 years ago
A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
3 years ago
Read 2 more answers
Two wires A and B of the same material, having radii in the ratio 1 : 2 and carry currents in the ratio 4 : 1. The ratio of drif
Brums [2.3K]

uhhhh idk cheif...                                                                                                                      

thats a big oof right there.

ged is always an option

3 0
4 years ago
The moment of inertia of a uniform-density disk rotating about an axle through its center can be shown to be . This result is ob
Naddik [55]

(a) 0.2888 kg m^2

The moment of inertia of a uniform-density disk is given by

I=\frac{1}{2}MR^2

where

M is the mass of the disk

R is its radius

In this problem,

M = 16 kg is the mass of the disk

R = 0.19 m is the radius

Substituting into the equation, we find

I=\frac{1}{2}(16 kg)(0.19 m)^2=0.2888 kg m^2

(b) 142.5 J

The rotational kinetic energy of the disk is given by

K=\frac{1}{2}I\omega^2

where

I is the moment of inertia

\omega is the angular velocity

We know that the disk makes one complete rotation in T=0.2 s (so, this is the period). Therefore, its angular velocity is

\omega=\frac{2\pi}{T}=\frac{2\pi}{0.2 s}=31.4 rad/s

And so, the rotational kinetic energy is

K=\frac{1}{2}(0.2888 kg m^2)(31.4 rad/s)^2=142.5 J

(c) 9.07 kg m^2 /s

The rotational angular momentum of the disk is given by

L=I\omega

where

I is the moment of inertia

\omega is the angular velocity

Substituting the values found in the previous parts of the problem, we find

L=(0.2888 kg m^2)(31.4 rad/s)=9.07 kg m^2 /s

8 0
3 years ago
H e l p a h o m i e o u t t h a n k s
finlep [7]
Uh it’s D i’m pretty sure
4 0
3 years ago
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