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laiz [17]
2 years ago
6

How many liters of carbon dioxide gas are there in 4 moles of CO2 at STP?

Chemistry
1 answer:
Ad libitum [116K]2 years ago
4 0

Answer:

<u>89.6 L</u>

Explanation:

In normal conditions,

<u><em>For every </em></u><u><em>1 mole</em></u><u><em> of carbon dioxide at STP, it occupies </em></u><u><em>22.4 L</em></u><u><em> of volume.</em></u>

<u><em /></u>

============================================================

Solving :

⇒ 1 mole : 22.4 L

⇒ 1 × 4 : 22.4 × 4

⇒ 4 moles : <u>89.6 L</u>

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slava [35]

H₂ + ½O₂ → H₂O

2g → 18g

So, 18g water needs 2g H₂

So, 1g water needs 2/18g H₂

So, 180g water needs 2/18 x 180g H₂

→ 20 litres of H₂

6 0
3 years ago
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Convert 27.7 kilometers to centimeters.
Stolb23 [73]

Answer:

The correct answer is - 2770000 cm.

Explanation:

1 kilometer = 1000 meter

1 meter = 100 centimeter

1 kilometer = 100*1000 cm

1 km = 100000 cm.

then,

27.7 kilometers = 2.77 × 10^6 centimeters

So, 27.7 kilometers = 27.7 × 100000

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7 0
3 years ago
Measurements include
Keith_Richards [23]
There’s lots of measurements. (m, kg, s, mol, cm, in, mm) etc
8 0
3 years ago
Suppose a compound is involved in three different reactions denoted R1, R2, and R3. Tripling the concentration of this reactant
pickupchik [31]

Answer:

The order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

Explanation:

The rate of a chemical reaction is the number of moles of reactants consumed per unit time or the number of moles of products formed per unit. the rate of a chemical reaction is affected by the concentration of reactants

The relationship between the rate of a chemical reaction and the concentration of its reactants is given by the rate law or equation.

Generally, the rate equation is given as;

Rate = k[A]ᵃ[B]ᵇ..., where k = rate constant which is independent of concentration of the reactants, [A] = concentration of reactant A, a = order of reaction A, [B] = concentration of reaction B, b = order of reaction B.

For the given reactions R1, R2 and R3

For R1; rate = 3, Concentration = 3[A]

3 = k[A]3ˣ

3¹ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 1

For R2; rate = 9, Concentration = 3[A]

9 = k[A]3ˣ

3² = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 2

For R1; rate = 1, Concentration = 3[A]

1 = k[A]3ˣ

3⁰ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 0

Therefore, the order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

6 0
3 years ago
Describe the electron sharing between 2 oxygen atoms
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When two oxygen atoms get close to each other, the attractions from the nucleus of both atoms attract the outer electrons.

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