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JulijaS [17]
3 years ago
14

carbon disulfide is formed by the reaction of coke (carbon) with sulfur dioxide. how many moles of cs2 will be generated if 8.0

moles of coke react with a surplus of sulfur dioxide?
Chemistry
1 answer:
Murrr4er [49]3 years ago
7 0
5C₂ + 4SO₂ ------>  2CS₂  +  8CO

mole ratio of C₂  :  CS₂
                 =   5   :    2

∴ since C₂ contains 8 moles 

  then CS₂ contain   ( \frac{8}{5} )  *  2  moles
                            
                             =  3.2 moles
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According to de Broglie, which of these objects does not have a wavelength?
polet [3.4K]

Answer: Option D is correct.

Explanation: Equation given by de Broglie is:

\lambda =\frac{h}{mv}

where, \lambda = wavelength of the particle

h = Planck's constant

m = mass of the particle

v = velocity of the particle

In option A, football will have some mass and is moving with a velocity of 25 m/s, hence it will have some wavelength.

In Option B, unladen swallow also have some mass and is moving with a velocity of 38 km/hr, hence it will also have some wavelength.

In Option C, a person has some mass and is running with a velocity of 7 m/hr, hence it will also have some wavelength.

As, the momentum of these particles are large, therefore the wavelength will be of small magnitude and hence, is not observable.

From the above, it is clearly visible that all the options are having some wavelength, so option D is correct.

7 0
3 years ago
How are we made from star debris? What does this mean? Explain
4vir4ik [10]

Answer:

How star stuff got to Earth

When it has exhausted its supply of hydrogen, it can die in a violent explostion, called a nova. The explosion of a massive star, called a supernova, can be billions of times as bright as the Sun , according to "Supernova," (World Book, Inc., 2005). Such a stellar explosion throws a large cloud of dust and gas into space, with the amount and composition of the material expelled varying depending on the type of supernova.

A supernova reaches its peak brightness a few days after it first occurred, during which time it may outshine an entire galaxy of stars. The dead star then continues to shine intensely for several weeks before gradually fading from view, according to "Supernova."

The material from a supernova eventually disperses throughout interstellar space. The oldest stars almost exclusively consisted of hydrogen and helium, with oxygen and the rest of the heavy elements in the universe later coming from supernova explosions, according to "Cosmic Collisions: The Hubble Atlas of Merging Galaxies," (Springer, 2009).

"It's a well-tested theory," Impey said. "We know that stars make heavy elements, and late in their lives, they eject gas into the medium between stars so it can be part of subsequent stars and planets (and people)."

Cosmic connections

So, all life on Earth and the atoms in our bodies were created in the furnace of now-long-dead stars, he said.

In 2002, music artist Moby released "We Are All Made of Stars," explaining during a press interview that his lyrics were inspired by quantum physics. "On a basic quantum level, all the matter in the universe is essentially made up of stardust," he said.

Explanation:

7 0
3 years ago
Mass, size, and color are examples of what?
Igoryamba
Physical properties of matter
3 0
3 years ago
How long would it take for 1.50 mol of water at 100.0 âc to be converted completely into steam if heat were added at a constant
defon
To convert boiling water to steam, that would involve heat of vaporization. The heat of vaporization for water at atmospheric conditions is: ΔHvap = <span>2260 J/g.

Molar mass of water = 18 g/mol

Q = m</span>ΔHvap = (1.50 mol water)(18 g/mol)(<span>2260 J/g) = 61,020 J

Time = Q/Rate = (61,020 J)(1 s/20 J) = 3051 seconds

In order to express the answer in three significant units, let's convert that to minutes.
Time = 3051 s * 1min/30 s = <em>102 min</em></span>
6 0
3 years ago
For the titration of 25.00 mL of 0.150 M HCl with 0.250 M NaOH, calculate:
Leviafan [203]
1) Chemical reaction

HCl        +       NaOH      --->      NaCl + H2O

25.0 ml            
0.150 M            0.250M

2) 50% completion => 0.025 l * 0.150 M * (1/2) = 0.001875 mol HCl consumed and 0.001875 mol HCl in solution

0.001875 mol HCl => 0.001875 mol H(+)

Volume = Volume of HCl solution + Volumen of NaOH solution added

Volume of HCl solution = 0.0250 l

Volume of NaOH = n / M = 0.001875 mol / 0.250M = 0.0075 l

Total volume = 0.0250 l + 0.0075 l = 0.0325 l

[H+] = 0.001875 mol / 0.0325 l = 0.05769 M

pH = - log [H+] = - log (0.05769) = 1.23

Answer: 1.23

3) Equivalence point

0.02500 l * 0.150 M = 0.250M * V

=> V = 0.02500 * 0.150 / 0.250 = 0.015 l

4) 1.00 ml NaOH added beyond the equivalence point

1.00 ml * 1 l / 1000 ml * 0.250 M = 0.00025 mol NaOH in excess

0.00025 mol NaOH = 0.00025 mol OH-

Volume of the solution = 0.02500 l + 0.015 l + 1.00/1000 l = 0.041 l

[OH-] = 0.00025 mol / 0.041 l = 0.00610 M

pOH = - log (0.00610) = 2.21

pH + pOH = 14 => pH = 14 - pOH = 14 - 2.21 = 11.76

Answer: 11.76
6 0
3 years ago
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