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k0ka [10]
4 years ago
6

Alice and Tom dive from an overhang into the lake below. Tom simply drops straight down from the edge, but Alice takes a running

start and jumps with an initial horizontal velocity of 25 m/s. Neither person experiences any significant air resistance. Just as they reach the lake below Question 15 options:
A. the speed of Alice is larger than that of Tom.
B. the splashdown speed of Alice is larger than that of Tom.
C. the speed of Tom will always be 9.8 m/s larger than that of Alice.
D. the speed of Alice will always be 25 m/s larger than that of Tom. e) they will both have the same speed.
Physics
1 answer:
alina1380 [7]4 years ago
4 0

Answer:

D, ---- Not sure

Explanation:

No air resistance

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you have two pendulums with cords that are exactly the same length. one is on earth (with an acceleration due to gravity of 9.81
olga55 [171]
From  T = 2π√(l/g).

Since the lengths are the same, so that is a constant.

T α 1/√g

So the period T is inversely proportional to the square root of gravity g.

So the one with a bigger gravity g would have a shorter period

and

the one with smaller gravity g would have a longer period.

Therefore the period on the Moon with gravity of 1.63 m/s² would be longer period than that on the Earth with gravity of 9.81 m/s² 
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3 years ago
You are explaining to your friends why astronauts feel weightless while orbiting in the space shuttle. They ask you to prove thi
meriva

Answer:

Explanation:

Force of gravity = GMm/r^2 = ma

a being the acceleration due to gravity at some distance r from the center of the Earth.  I'll use 6400 km for the radius of the Earth so r = 6734 km or 6734000 meters

a = GM/r^2

plugging in G = 6.67 x 10^-11

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and r is from above

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3 years ago
A drop in pitch as a vehicle passes is known as the effect
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The Doppler Effect...

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Check all of the following statements which are true. (You may need to consult Section 7.6 in the textbook.) You should check an
IrinaVladis [17]

Answer:

D

Explanation:

8 0
4 years ago
Compare these two collisions of a PE student with a wall.
Stolb23 [73]

1) The variable that is different in the two cases is \Delta t, the duration of the collision

2) The change in momentum is the same in the two cases

3) The impulse is the same in the two cases

4) Case B will experience a greater force

Explanation:

1)

The variable that is different in the two cases is \Delta t, the duration of the collision.

In fact, in the first case the wall is padded: this means that the collision will be "softer" and therefore will last longer, so the duration of the collision, \Delta t, will be larger.

In the second case instead, the wall is unpadded: this means that the collision is "harder" and so it will last less time, therefore the duration of the collision \Delta t will be smaller.

2)

The change in momentum in the two cases is the same.

In fact, the change in momentum is given by:

\Delta p = m(v-u)

where:

m is the mass of the student

u is the initial velocity

v is the final velocity

In both cases, we have:

m = 75 kg

u = 8 m/s

v = 0 (they both comes to rest)

Therefore, the change in momentum is

\Delta p = (75)(0-8)=-600 kg m/s

3)

The impulse in the two cases is the same.

In fact, impulse is defined as the product of force applied, F, and duration of the collision, \Delta t:

J=F \Delta t

However, the force can be rewritten as product of mass (m) and acceleration (a), according to Newton's second law:

F=ma

So the impulse is

J=ma\Delta t

The acceleration can be rewritten as rate of change of velocity:

a=\frac{\Delta v}{\Delta t}

So the impulse becomes

J=m\frac{\Delta v}{\Delta t}\Delta t = m\Delta v

So, the impulse is equal to the change in momentum: and since in the two cases the change in momentum is the same, the impulse is the same as well.

4)

The force in the collision is related to the impulse by

J=F\Delta t

where

J is the impulse

F is the force

\Delta t is the duration of the collision

The equation can be rewritten as

F=\frac{J}{\Delta t}

In the two situations described in the problem (A and B), we already said that the impulse is the same (because the change in momentum is the same). However, in case A (padded wall) the time \Delta t is longer, while in case B (unpadded wall) the time \Delta t is shorter: since the force F is inversely proportional to the duration of the collision, this means that in case B the student will experience a greatest force compared to case A.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

3 0
4 years ago
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