A mass of (200 g) of hot water at (75.0°C) is mixed with cold water of mass M at (5.0°C). The final temperature of the mixture i

Question

2 years ago

13

s (25.0°C). What is the mass of the cold water (M)?

1 answer:

SIZIF [17.4K] · Answer 1 · 2023-07-31T04:15:07+03:00

The mass of the cold water, given the data from the question is 500 g

<h3>Data obtained from the question</h3>

<h3>How to determine the mass of the cold water </h3>

Heat loss = Heat gain

MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – T꜀)

200 × 4.184 (75 – 25) = M꜀ × 4.184(25 – 5)

41840 = M꜀ × 83.68

Divide both side 83.68

M꜀ = 41840 / 83.68

M꜀ = 500 g

Learn more about heat transfer:

#SPJ1