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Law Incorporation [45]
2 years ago
5

A 15.0 L rigid container was charged with 0.5 atm of Krypton gas and 1.5 atm of chlorine gas at 350 C. The krypton and chlorine

react to form tetrachloride. What mass of krypton tetrachloride can be produced assuming 100% yield?
Chemistry
1 answer:
Angelina_Jolie [31]2 years ago
4 0

The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as

molar mass=33.29g

<h3>What mass of krypton tetrachloride can be produced assuming 100% yield?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Therefore

n=(0.50)(15.)/0.082*623

n=0.147mol

Hence for clorine

n=0.441mol

Given the reaction

Kr+2cl2---->KrCL4

Hence

molar mass=225.60*0.147

molar mass=33.29g

Read more about Chemical Reaction

brainly.com/question/11231920

#SPJ1

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Answer:

  • <em>The volume of 14.0 g of nitrogen gas at STP is </em><u><em>11.2 liter.</em></u>

Explanation:

STP stands for standard pressure and temperature.

The International Institute of of Pure and Applied Chemistry, IUPAC changed the definition of standard temperature and pressure (STP) in 1982:

  •   Before the change, STP was defined as a temperature of 273.15 K and an absolute pressure of exactly 1 atm (101.325 kPa).

  •    After the change, STP is defined as a temperature of 273.15 K and an absolute pressure of exactly 105 Pa (100 kPa, 1 bar).

Using the ideal gas equation of state, PV = nRT you can calculate the volume of one mole (n = 1)  of gas. With the former definition, the volume of a mol of gas at STP, rounded to 3 significant figures, was 22.4 liter. This is classical well known result.

With the later definition, the volume of a mol of gas at STP is 22.7 liter.

I will use the traditional measure of 22.4 liter per mole of gas.

<u>1) Convert 14.0 g of nitrogen gas to number of moles:</u>

  • n = mass in grams / molar mass
  • Atomic mass of nitrogen: 14.0 g/mol
  • Nitrogen gas is a diatomic molecule, so the molar mass of nitrogen gas = molar mass of N₂ = 14.0 × 2 g/mol = 28.0 g/mol
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<u>2) Set a proportion to calculate the volume of nitrogen gas:</u>

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  • Solve for x: x = 0.500 mol × 22.4 liter / mol = 11.2 liter.

<u>Conclusion:</u> the volume of 14.0 g of nitrogen gas at STP is 11.2 liter.

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