What will be the weight of a man of mass 90kg when he is on a planet with acceleration due to gravity of 15ms-2?
1 answer:
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Answer:
a) 23.2 e V
b) energy of the original photon is 36.8 eV
Explanation:
given,
energy at ground level = -13.6 e V
energy at first exited state = - 3.4 e V
A photon of energy ionized from ground state and electron of energy K is released.
h ν₁ - 13.6 = K
K combine with photon in first exited state giving out photon of energy
= 26.6 e V
h c = 6.626 × 10⁻³⁴ × 3 × 10⁸ = 12400 e V A°
K + ( 3.4 ) = 26.6 e V
a) energy of free electron
K = 26.6 - 3.4 = 23.2 e V
b) energy of the original photon
h ν₁ - 13.6 = K
h ν₁ = 23.2 + 13.6
= 36.8 e V
energy of the original photon is 36.8 eV
We know that velocity is equal to the total displacement of an object over time.
Deriving from that equation, we can say that:
Okay, so here it goes:
The bicycle took 25.02 seconds to displace at 58.3 meters.
Deriving from that equation, we can say that:
Okay, so here it goes:
The bicycle took 25.02 seconds to displace at 58.3 meters.