1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IRISSAK [1]
3 years ago
8

Given the chemical reaction Na2CO3 + AgNO3 , will a precipitate be formed?

Chemistry
1 answer:
stepladder [879]3 years ago
3 0
A precipitate will be formed through the double displacement method in chemical reactions. The chemical equation would be:
Na2CO3 + AgNO3 ----> NaNO3 + Ag2CO3.
Balancing would result to:
<span>Na2CO3 + 2AgNO3 ----> 2NaNO3 (aq)+ Ag2CO3.
</span>
Ag2CO3 is the precipitate formed. It is yellow in color but due to the presence of elemental silver, it is a bit grayish.
You might be interested in
Which orbital has the highest energy level
fgiga [73]

Answer:

p orbitals

Explanation:

3 0
3 years ago
Iron filings were mixed together with salt crystals. What unique property of iron would be BEST to separate the filings from the
Sedaia [141]
Iron has magnetic properties, so you would just need to hold a magnet over the mixture and the filings will come right out.
4 0
3 years ago
Read 2 more answers
F a balloon containing 1000 L of gas 50 Celsius and 101.3kpa rises to an altitude where pressure is 27.5 kpa amd the temperature
inna [77]

Answer:

V₂ =  3227.46 L

Explanation:

Given data:

Initial volume of gas = 1000 L

Initial temperature = 50°C  (50 +273 = 323 K)

Initial pressure = 101.3 KPa

Final pressure = 27.5 KPa

Final temperature = 10°C  (10 +273 = 283 K)

Final volume = ?

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 101.3 KPa × 1000 L × 283 K / 323 K × 27.5 KPa

V₂ = 28667900 KPa .L. K /   8882.5 K.KPa

V₂ =  3227.46 L

7 0
3 years ago
If a 1.00 mL sample of the reaction mixture for the equilibrium constant experiment required 32.40 mL of 0.258 M NaOH to titrate
andrey2020 [161]

Answer:

The concentration of acetic acid is 8.36 M

Explanation:

Step 1: Data given

Volume of acetic acid = 1.00 mL = 0.001 L

Volume of NaOH = 32.40 mL = 0.03240 L

Molarity of NaOH = 0.258 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate the concentration of the acetic acid

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = TO BE DETERMINED

⇒with Va = the volume of CH3COOH = 1.00 mL = 0.001L

⇒with a = the coefficient of CH3COOH = 1

⇒with Cb = the concentration of NaOH = 0.258 M

⇒with Vb = the volume of NaOH = 32.40 mL = 0.03240 L

Ca * 0.001 L = 0.258 * 0.03240

Ca = 8.36 M

The concentration of acetic acid is 8.36 M

6 0
3 years ago
Which term names the main class of the chemical that makes up bread.
Shkiper50 [21]

Answer:

yeast

Explanation:

4 0
3 years ago
Other questions:
  • Compozitia procentuala a NaCl
    6·1 answer
  • How many moles of PCl3 are produced if 5 moles of P4 reacted with 22 moles of Cl2
    14·1 answer
  • Can someone please help me with this
    10·2 answers
  • What is stratosphere
    13·1 answer
  • Which organelle is found in photosynthetic organisms and captures energy from the sun?
    8·2 answers
  • 3. DNA replication occurs:
    7·1 answer
  • The symbol equation for combustion of a hydrocarbon is shown below. What number will go before the oxygen reactant when
    15·1 answer
  • Determine the atomic number, atomic mass and element name of the following:
    13·1 answer
  • Is it possible to add an atom with 12 protons and 13 electrons explain​
    9·1 answer
  • A 50.0 mL sample of 0.10 M potassium nitrate is mixed with 100 mL of 0.25 M magnesium nitrate. What is the final concentration o
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!