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3 years ago

A farmer clears an area of land, and erosion washes away much of the topsoil. The

Physics

1 answer:

IgorC [24]3 years ago

6 0

Answer:b

Explanation:because it ony makes sence

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A object with a mass of 1.5 kg is lifted from the ground to a height of 0.22 m what is the objects potential energy

svet-max [94.6K]

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 1.5 × 10 × 0.22

We have the final answer as

Hope this helps you

5 0

2 years ago

Do mechanical waves transfer light energy?

Gekata [30.6K]

B ... A ... A ... B .

7 0

3 years ago

A 21.7kg child descends a slide 3.5 m high and reaches the bottom with a speed of 2.2m/s. How much thermal energy due to frictio

nadya68 [22]

Answer:

Subtract the kinetic energy at the bottom from the potential energy loss. The remainder becomes frictional heat.

Potential energy loss:

M g H = 21.7*9.81*3.5 = 745.1 J

Kinetic energy at bottom of slide:

= (1/2) M v^2 = 52.5 J

5 0

3 years ago

What is the new acceleration (in m/s/s)?

Delicious77 [7]

The new acceleration is $108 m/s^2$

Explanation:

We can answer this problem by applying Newton's second law, which states that:

$F=ma$

where

F is the net force on an object

m is the mass of the object

a is its acceleration

The equation can be rewritten as

$a=\frac{F}{m}$

In this problem, the initial acceleration is

$a=18.0 m/s^2$

Later:

- The net force is tripled: $F'=3F$

- The mass is halved: $m'=\frac{m}{2}$

Therefore, the new acceleration is:

$a'=\frac{F'}{m'}=\frac{3F}{m/2}=6\frac{F}{m}=6a$

which means that the new acceleration is 6 times the original acceleration, therefore

$a'=6(18)=108 m/s^2$

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

8 0

3 years ago

Starting from rest, a 6.79 kg block slides 2.82 m down a rough 20.7 ◦ incline. The coefficient of kinetic friction between the b

Veronika [31]

Answer:

23.52092 J

Explanation:

m = Mass of block = 6.79 kg

s = Sliding distance = 2.82 m

$\theta$ = Angle of slide = 20.7°

$\mu$ = Coefficient of kinetic friction = 0.425

g = Acceleration due to gravity = 9.8 m/s²

Work done by the force of gravity is given by

$W=mgsin\theta\\\Rightarrow W=6.79\times 9.8\times sin20.7\\\Rightarrow W=23.52092\ J$

The work done by the force of gravity is 23.52092 J

8 0

2 years ago