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VikaD [51]
3 years ago
6

A farmer clears an area of land, and erosion washes away much of the topsoil. The

Physics
1 answer:
IgorC [24]3 years ago
6 0

Answer:b

Explanation:because it ony makes sence

You might be interested in
Before CDs and cassette tapes, there were vinyl records. The most comon spun with an angular velocity of 33.3revolutionsperminut
sashaice [31]

Answer:

539.5°

Explanation:

33.3 revolutions per minute

1 revolution = 360°

1 minute = 60 seconds

hence

33.3 revs ----> 1 minute = 60 seconds

X revs -----------> 2.70 seconds

X = (33.3 x 2.7)÷60 = 1.4985 revolutions in 2.70 seconds

1.4985 revolutions = 1.4985 x 360 = 539.46

which is approximately 539.5°

7 0
3 years ago
Select the correct answer.
BaLLatris [955]

It is due to the excess stress.

6 0
3 years ago
A young woman walks up 55 steps to the top of a water slide. She slides
navik [9.2K]

Answer:

potential energy PE = M g h

KE at bottom = 1/2 M V^2

Regardless of the slope of the slide the change in energy is the same

1/2 V^2 = g h

V = (2 g h)^1/2 = (2 * 9.8 m/s^2 * 10 m)^1/2 = 14 m / s

Perhaps the question says that h = 55 * .1 = 5.5 m

Then V = (2 * 9.8 * 5.5) = 10.4 m/s

5 0
2 years ago
35. What would a ship's position be if that ship started at
Tcecarenko [31]

Answer:

The final position of the ship after the given time period is  42 km West of B.

Explanation:

Given;

average velocity of the ship, v = 35 km/h

time taken for the ship to reach point D, t = 1.2 hours

The position of the ship after the given time period is calculated as follows;

x = v x t

x = (35 km/h) x 1.2 h = 42 km

x  = 42 km West of B.

Therefore, the final position of the ship after the given time period is  42 km West of B.

5 0
3 years ago
1) Subatomic particles called muons can be created in the upper atmosphere by collisions of cosmic rays (energetic particles com
Vsevolod [243]

Answer and explanation:

A.

Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)

B.

In muon rest frame it travels Zero meters

C.

Distance, d = Velocity, v * Time, s

where, v = 0.9c = 0.9 \times 8 \times 10^8 , s = 2.2 \mu s

d = 0.9 \times 3 \times 10^8 \times 2.2 \times 10^{-6}\\\\d = 594m

D.

Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame

that is same as in part C which is 594m

E.

Using lorentz contraction

In the rest frame of someone standing on the mountain

the distance is given by

d' = \frac{d}{\gamma} = d\sqrt{1 - \frac{v^2}{c^2}}, where, \frac{1}{\gamma}= \sqrt{1 - \frac{v^2}{c^2}}

d' = 594\sqrt{1 - \frac{(0.9c)^2}{c^2}}

d' = 594\sqrt{1 - 0.81}

d' = 594 \times 0.4359

d' = 258.92m

F.

in the rest frame of someone standing on the mountain,

muon moves straight down

3 0
4 years ago
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