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Liula [17]
3 years ago
15

A ball is tied to a 1.3 m string and whirled in a circular motion with a force of 220 N. If its speed is 6 m/s, (a) what is it c

entripetal acceleration? (b) What is the mass of the ball?
Physics
1 answer:
Studentka2010 [4]3 years ago
6 0

The centripetal acceleration is 27.692 kg m / s^2.

The mass of the ball is 7.94 kg.

<u>Explanation:</u>

  • The curved path of an object experience a force known as centripetal force. Its direction is always pointing to the motion of the body towards the center of curvature of the path.

            centripetal force Fc = (mass * square of velocity) / radius

where m represents mass in kg

          v represents  velocity

          r represents radius in a meter.

  • The acceleration experienced in uniform circular motion is called as centripetal acceleration.It always points toward the center of rotation and is perpendicular to the linear velocity.
  •                     centripetal acceleration = v^2 / r

                                                             = (6 * 6) / 1.3

                                                             = 27.692 kg m / s^2.

 The mass of the ball is found by using the centripetal force formula,

  •                               centripetal force Fc = m v^2 / r

                                                      m = (F * r) / v^2

                                                          =  (220 * 1.3) / 36

                           mass of the ball  m = 7.94 kg.

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A motorcycle is speeding along at a velocity of120kph.Then, it changes to a velocity of 150 kph for 2 minutes.What is the motorc
Taya2010 [7]

Answer:

Explanation:

a=v-u/t

a=acceleration

v=final velocity

u=initial velocity

t=tme taken

we need to convert from kph to ms⁻¹

v= 150*1000/60*60= 41.67ms⁻¹

u= 120*1000/60*60= 33.33ms⁻¹

t= 2*60= 120s

a=41.67-33.33/120

a=8.34/120

a=0.0694ms⁻²

8 0
2 years ago
If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?
steposvetlana [31]

Hi there!

\large\boxed{\text{B) 20 meters}}

We know that:

E_T = U + K

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

<u>h = 20 meters</u>

3 0
2 years ago
The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in
MissTica

Answer:

<em>155.80rad/s</em>

Explanation:

Using the equation of motion to find the angular acceleration:

\omega_f = \omega_i + \alpha t

\omega_f is the final angular velocity in rad/s

\omega_i  is the initial angular velocity in rad/s

\alpha is the angular acceleration

t is the time taken

Given the following

\omega_f = 6100rpm

Time = 4.1secs

Convert the angular velocity to rad/s

1rpm = 0.10472rad/s

6100rpm = x

x = 6100 * 0.10472

x  = 638.792rad/s

\omega_f = 638.792rad/s\\

Get the angular acceleration:

Recall that:

\omega_f = \omega_i + \alpha t

638.792 = 0 + ∝(4.1)

4.1∝ = 638.792

∝ = 638.792/4.1

∝ = 155.80rad/s

<em>Hence the angular acceleration as the blades slow down is 155.80rad/s</em>

5 0
2 years ago
A new ski area has opened that emphasizes the extreme nature of the skiing possible on its slopes. Suppose an ad intones "Free-f
Allushta [10]

Answer:

48.6°

Explanation:

The forward force, F equals the component of the weight along the slope.

So mgsinθ = ma where a = acceleration and θ = angle between the slope and the horizontal.

So a = gsinθ

Since we are given that a = 75%g = 0.75g,

0.75g = gsinθ

sinθ = 0.75

θ = sin⁻¹(0.75)

= 48.6°

5 0
3 years ago
How is your guys day going?​
faltersainse [42]
Good i’m tired how about you
4 0
3 years ago
Read 2 more answers
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