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blondinia [14]
2 years ago
9

An object weighs 200N on earth What would be its mass on the moon

Physics
2 answers:
Kamila [148]2 years ago
8 0

Mass will be same on moon as it was  on earth

<h3></h3><h3>What is mass ?</h3>

Mass is the measure of inertia or the amount of matter in body .It is a property of matter .

since, it is a property of matter and we know that amount of matter will remain same no matter the place . Amount of matter will same even at moon as it was on earth .

hence , mass will remain same irrespective of place

It will be same on moon as it was  on earth

learn more about mass

brainly.com/question/19796325?referrer=searchResults

#SPJ2

lorasvet [3.4K]2 years ago
7 0
The mass is the same no matter where the object is, but the weight on the moon changes because gravity is weaker there. So the mass is m = 20N/9.81 m/s^2 = 2.04kg
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Which circuit offers the greater resistance to the battery, two bulbs in series or two bulbs in parallel?
dolphi86 [110]

The resistance of two things in series is the SUM of their individual resistances.  So the resistance of two bulbs in series is <u><em>double</em></u> the resistance of one bulb.

(If they're in parallel, their combined resistance is <u><em>1/2</em></u> the resistance of one bulb.)

So two bulbs <em>in series</em> is the greater resistance. <em>(a) </em>

7 0
3 years ago
You hear three beats per second when two sounds tones are generated. The frequency of one tone is known to be 610 Hz. The freque
tiny-mole [99]

The frequency of the other wave is 613 Hz or 607 Hz.

The difference between the frequencies of two waves is called the beat frequency.

Here, one wave has a frequency 610 Hz and the beat frequency is 3 beats per second.

Which has a higher frequency is not mentioned. Therefore, there are two possibilities.

Δf = | 610 - 613 | = 3

or

Δf = | 610 - 607 | = 3

Therefore, the frequency of the other wave is 613 Hz or 607 Hz.

Learn more about beat frequency here:

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7 0
2 years ago
A spring with a spring constant of 165 N/m is attached to a 2.0 kg mass and set into motion.
marin [14]

Explanation:

We have,

Spring constant of the spring, k = 165 N/m

Mass, m = 2 kg

It is required to find the period of the mass-spring system. For the spring mass system, the period is given by :

T=2\pi \sqrt{\dfrac{m}{k} }\\\\T=2\pi \sqrt{\dfrac{2}{165} }\\\\T=0.69\ s

The frequency of vibration is reciprocal of its time period. So,

f=\dfrac{1}{T}\\\\f=\dfrac{1}{0.69}\\\\f=1.44\ Hz

So, the period of the mass-spring system is 0.69 s and frequency is 1.44 Hz.

3 0
4 years ago
A plane on the ground will weigh:
kenny6666 [7]

On ground weight of plane will be measured as its actual weight which will be given as

W = mg

now when plane is in air its weight is measured as combined effect of earth gravitational force and buoyancy force both

so weight in air will be given as

W_{air} = mg - F_b

here since net effect due to air is opposite to the direction of weight so in air the plane weight will be measure less than its weight on ground.

so answer will be

A)more than a plane in the air

3 0
3 years ago
Read 2 more answers
A narrow beam of white light is incident on a sheet of quartz. Thebeam disperses in the quartz, with red light (λË700nm)traveli
uysha [10]

Answer:

The index of refraction of quartz for violet light is 1.47.

Explanation:

It is given that, a narrow beam of white light is incident on a sheet of quartz.

The beam disperses in the quartz, with red light at an angle, \theta_r=26.3^{\circ} wrt to the normal and violet light traveling at an angle of \theta_v=25.7^{\circ}

The index of refraction of quartz for red light is 1.45.

We need to find the index of refraction of quartz for violet light.

Using Snell's law of red light as follows :

\mu_a\sin\theta_i=\mu_r\sin\theta_r

Here,

\mu_a is the refractive index of air

\theta_i is the angle of incidence

We can find the value of angle of incidence as follows :

\sin\theta_i=\dfrac{\mu_r \sin\theta_r}{\mu_a}\\\\\sin\theta_i=\dfrac{1.45\times  \sin(26.3)}{1}\\\\\theta_i=\sin^{-1}(0.642)\\\\\theta_i=39.79^{\circ}

Now again using Snell's law for violet light as follows :

\mu_a\sin\theta_i=\mu_v\sin\theta_v\\\\\mu_v=\dfrac{\mu_a\sin\theta_i}{\sin\theta_v}\\\\\mu_v=\dfrac{1\times \sin(39.79)}{\sin(25.7)}\\\\\mu_v=1.47

So, the index of refraction of quartz for violet light is 1.47.

6 0
4 years ago
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