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oksian1 [2.3K]
2 years ago
10

A person skateboarding is part of a closed system that has 1,450 j of

Physics
1 answer:
soldier1979 [14.2K]2 years ago
6 0

The gravitational potential energy of the system will decreases from 1,250 J to 625 J. Option A is corect.

<h3>What is the law of conservation of energy?</h3>

According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.

The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.

TE=KE+GPE

Case 1;

1450 = 200 J+GPE

GPE=1450 -200

GPE=1250 J

Case 2;

1450 = 825 J+GPE

GPE=1450 -825

GPE=625 J

The gravitational potential energy of the system will decreases from 1,250 J to 625 J.

Hence, option A is corect.

To learn more about the law of conservation of energy, refer to brainly.com/question/2137260.

#SPJ1

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A cube has a drag coefficient of 0.8. what would be the terminal velocity of a sugar cube 1 cm on a side in air (ρ = 1.2 kg/m3)?
kramer
To answer this question, we should know the formula for the terminal velocity. The formula is written below:

v = √(2mg/ρAC)
where
m is the mass
g is 9.81 m/s²
ρ is density
A is area
C is the drag coefficient

Let's determine the mass, m, to be density*volume.
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v = √(2*1.6×10⁻³ kg*9.81 m/s²/1.6×10³ kg/m³*10⁻⁴ m²*0.8)
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3 years ago
A projectile fired up into the air at an angle has a range of 235 m and a flight time of 47 s.
madam [21]
<h2>Answer:5ms^{-1},133.6m,51.18ms^{-1}</h2>

Explanation:

Let v_{x},v_{y} be the horizontal and vertical components of velocity.

Question a:

Horizontal component of velocity is the ratio of range and time of flight.

So,horizontal component of velocity is \frac{235}{47}=5ms^{-1}

So,v_{x}=5ms^{-1}

Question b:

Time of flight=\frac{2v_{y}}{g}

So,v_{y}=\frac{47\times 9.8}{2}=51.18ms^{-1}

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So,maximum height is \frac{51.18^{2}}{2\times 9.8}=133.6m

Question c:

The vertical velocity is already calculated in Question b.

v_{y}=51.18ms^{-1}

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