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1 year ago

Consider the balanced reaction

Chemistry

1 answer:

VARVARA [1.3K]1 year ago

4 0

The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g

<h3>What is the use of aluminium chloride ?</h3>

Aluminum chloride is useful for the treatment of palmar, plantar, and axillary hyperhidrosis.

Aluminum chloride has also been reported to be useful in facial and scalp hyperhidrosis

The balanced chemical equation represents the mole ratio in which the chemicals combine.

In this case, illustrates that 2 mol Al produces 2 mol Al Cl₃, hence these 2 chemicals are in a 1:1 ratio.

Thus, to produce 8.70 mol aluminium chloride, it will require 8.70 mol aluminium.

But this quantity of Al has a mass in grams of

m = n × Mr

= 8.70 mol × 27g/mol

= 234.9 g

Hence, The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g

Learn more about mole concept here ;

https://brainly.in/question/12599804

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Answer:

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Explanation:

Here Pressure in a container is given as

$P=\frac{1}{3} \rho$

Here

P is the pressure which is to be calculated

ρ is the density of the gas which is to be calculated as below

$\rho =\frac{mass}{Volume of container}$

Here

mass is to be calculated for 75 gas phase molecules as

$m=n_{molecules} \times \frac{1 mol}{6.022 \times 10^{23} molecules} \times \frac{32 g/mol}{1 mol}\\m=75 \times \frac{1 mol}{6.022 \times 10^{23} molecules} \times \frac{32 g/mol}{1 mol}\\m=3.98 \times 10^{-21} g$

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So density is given as

$\rho =\frac{mass}{Volume of container}\\\rho =\frac{3.98 \times 10^{-21} \times 10^{-3} kg}{0.5 \times 10^{-3} m^3}\\\rho =7.97 \times 10^{-21}\, kg/m^3$

is the mean squared velocity which is given as

$=RMS^2$

Here RMS is the Root Mean Square speed given as 605 m/s so

$=RMS^2\\=(605)^2\\=366025$

Substituting the values in the equation and solving

$P=\frac{1}{3} \rho \\P=\frac{1}{3} \times 7.97 \times 10^{-21} \times 366025\\P=9.72 \times 10^{-16} Pa$

So the average pressure in the container due to these 75 gas molecules is $P=9.72 \times 10^{-16} Pa$

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