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Semmy [17]
1 year ago
14

Consider the balanced reaction

Chemistry
1 answer:
VARVARA [1.3K]1 year ago
4 0

The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g

<h3>What is the use of aluminium chloride ?</h3>

Aluminum chloride is useful for the treatment of palmar, plantar, and axillary hyperhidrosis.

Aluminum chloride has also been reported to be useful in facial and scalp hyperhidrosis

The balanced chemical equation represents the mole ratio in which the chemicals combine.

In this case, illustrates that 2 mol Al produces 2 mol Al Cl₃, hence these 2 chemicals are in a 1:1 ratio.

Thus, to produce 8.70 mol aluminium chloride, it will require 8.70 mol aluminium.

But this quantity of Al has a mass in grams of

m = n × Mr

   = 8.70 mol × 27g/mol

   = 234.9 g

Hence, The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g

Learn more about mole concept here ;

https://brainly.in/question/12599804

#SPJ1

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Answer:

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Explanation:

the cuttle fish tell the difference between blue and yellow

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A dose of aspirin of 5.0 mg per kilogram of body weight has been prescribed to reduce the fever of an infant weighing 8.5 pounds
Tanya [424]
<h3><u>Answer</u>;</h3>

19 mg

<h3><u>Explanation</u>;</h3>

dose = 5.0 mg/kg  

weight of infant = 8.5 pounds

Convert 8.5 pounds to kg: 8.5 pounds = 3.86 kg

Therefore;

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How many moles are in 120g of NH3
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Moles of NH₃ : = 7.059

<h3>Further explanation</h3>

Given

120 g NH₃

Required

moles NH₃

Solution

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Moles can also be determined from the amount of substance mass and its molar mass

Mol = mass : Molar mass

So for 120 g (molar mass of NH₃ = 17 g/mol) :

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