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3 years ago

Match the technology that uses radio waves to the field in which it is used

Physics

1 answer:

Elden [556K]3 years ago

5 0

Answer:

Naturally occurring radio waves are made by lightning or by astronomical objects. Artificially generated radio waves are used for fixed and mobile radio communication, broadcasting, radar and other navigation systems, communications satellites, computer networks and innumerable other applications.

Explanation:

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In this circuit the resistance R1 is 7 Ω and R2 is 3 Ω. If this combination of resistors were to be replaced by a single resisto

Scilla [17]

Answer:

Series combination:

Equivalent resistance =10Ω

Parallel combination:

Equivalent resistance $=\frac{21}{10} \Omega$

Explanation:

Resistance: Resistance is the ratio of voltage to the current.

$R=\frac{V}{I}$

R = resistance

I = current

V= potential difference(voltage)

There are two types of resistance combinations.

series combination
parallel combination.

Series combination: If the ending point of one resistance is connected to the starting point of other resistance that combination is known as series combination.

If R₁,R₂ and R₃ are connected in series combination.

Then equivalent resistance = R₁+R₂+R₃

Parallel combination: If the ending point and the starting point of the all resistance are the same points that combination is known as parallel combination.

If R₁,R₂ and R₃ are connected in parallel combination.

Then equivalent resistance $\frac{1}{R}= \frac{1}{R_1}+ \frac{1}{R_2}+\frac{1}{R_3}$

Here R₁=7Ω and R₂=3Ω

If R₁ and R₂ connected in series combination

Then equivalent resistance = (7+3) Ω

=10Ω

If R₁ and R₂ connected in parallel combination

Then equivalent resistance $=\frac{1}{(\frac{1}{7} +\frac{1}{3})} \Omega$

$=\frac{21}{10} \Omega$

5 0

3 years ago

In the long jump, an athlete launches herself at an angle above the ground and lands at the same height, trying to travel the gr

NikAS [45]

A) 2.64t

B) 2.64h

C) 2.64D

Explanation:

The motion of the athlete is equivalent to the motion of a projectile, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion (constant acceleration) along the vertical direction

The time of flight of a projectile can be found from the equations of motion, and it is found to be

$t=\frac{2u sin \theta}{g}$

where

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the time of flight is $t$ .

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. Therefore, the time of flight on Mars will be:

$t'=\frac{2usin \theta}{g'}=\frac{2u sin \theta}{0.379g}=\frac{1}{0.379}t=2.64t$

The maximum height reached by a projectile can be also found using the equations of motion, and it is given by

$h=\frac{u^2 sin^2\theta}{2g}$

where

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the maximum height is $h$ .

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. So, the maximum height reached on Mars will be:

$h'=\frac{u^2 sin^2\theta}{2g'}=\frac{u^2 sin^2\theta}{(0.379)2g}=\frac{1}{0.379}h=2.64h$

The horizontal distance covered by a projectile is also found from the equations of motion, and it is given by

$D=\frac{u^2 sin(2\theta)}{g}$

where:

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the horizontal distance covered is D.

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. Therefore, the horizontal distance reached on Mars will be:

$D'=\frac{u^2 sin(2\theta)}{g'}=\frac{u^2 sin(2\theta)}{(0.379)g}=\frac{1}{0.379}D=2.64D$

7 0

3 years ago

A 0.010 kg clay ball thrown right at 16 m/s hits a marble moving left at 8.0 m/s, and sticks to it. Both move left at 3.2 m/s af

Anettt [7]

.……… it will be 7.5m/s

6 0

3 years ago

Read 2 more answers

All moving objects don’t have momentum<br> A. True<br> B. False

mestny [16]

Answer:

Explanation:

Some objects gain momentum.

4 0

2 years ago

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The cardiovascular system consists of

guapka [62]

Consists of A. good luck

3 0

3 years ago