<h3>
Answer:</h3>
147.05 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
CuClO₃
<u>Step 2: Find MM</u>
Molar Mass of Cu - 63.55 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CuClO₃ - 63.55 + 35.45 + 3(16.00) = 147.05 g/mol
Answer:
E = 3.9 x 10⁻²⁰ J
Explanation:
<u>Step 1:</u>
Before you can find the energy of the light, you need to find the wavelength. To find the wavelength, you need to use two equations:
w = c / f
In this formula, "w" is the wavelength (m), "c" is the speed of light (m/s), and "f" is the frequency. "C" is a constant with the value 3.0 x 10⁸ m/s. Since you have been given frequency and the constant, you can plug these values into the equation and solve for wavelength.
w = c / f
w = (3.0 x 10⁸ m/s) / (5.9 x 10¹³ sec⁻¹)
w = 5.1 x 10⁻⁶ m
<u>Step 2:</u>
To find the energy, you need to use the following equation:
E = hc / w
In this formula, "E" is the energy (J), "h" is Planck's constant (J/s), and "c" and "w" are the same as above. "H" is a constant with the value 6.626 x 10⁻³⁴ J/s. Since you found the wavelength and have been given the constants, you can plug them into the equation and find energy.
E = hc / w
E = (6.626 x 10⁻³⁴ J/s)(3.0 x 10⁸ m/s) / (5.1 x 10⁻⁶ m)
E = (1.99 x 10⁻²⁵) / (5.1 x 10⁻⁶ m)
E = 3.9 x 10⁻²⁰ J
Answer:
the answer is 119.0023 grams
<u>Answer:</u>
<em>The option which is true to the knowledge is second option.
</em>
<u>Explanation:</u>
The second option tells us that the attraction between the molecules is weak and movement of particles is less. Hence it makes the state x to be liquid because in case of liquid above the given fact is true to the knowledge.
While the other options are contradicting in nature for example if it is a solid that reaction will be strong and the movement will be very weak. And in case of gas that reaction will be very weak and movement will be very strong.
