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Svetach [21]
2 years ago
9

Preparation of ammonia gas​

Chemistry
1 answer:
Makovka662 [10]2 years ago
7 0

Answer:

Ammonia is easily made in the laboratory by heating an ammonium salt, such as ammonium chloride NH4Cl with a strong alkali, such as sodium hydroxide or calcium hydroxide.

The gas may also be made by warming concentrated ammonium hydroxide.

Explanation:

2NH4Cl + Ca(OH)2 → CaCl2 + 2H2O + 2NH3(g)

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Verdich [7]
Water is produce bases and says
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3 years ago
How do chemist and physical science relate?
Alex_Xolod [135]
The branch of chemist is a substance of science and pysical is the land science such as a desert of a forest those are chemist and physical science have a good day :)

8 0
3 years ago
What is the mass, in grams, of 9.01 x 1024 molecules of methanol (CH, OH) ?
Zina [86]

Answer:

480.6 g

Explanation:

Given data:

Number of molecules of methanol = 9.01 ×10²⁴

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

9.01 ×10²⁴molecules ×1 mol /6.022 × 10²³ molecules

1.5 ×10¹ mol

15 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 15 mol × 32.04 g/mol

Mass = 480.6 g

3 0
3 years ago
5. A standardized mass was known to weigh exactly 5.0000g. It was weighed on a newly
sergey [27]

Answer:

Absolute error = 0.001

% Error = 002 5

Explanation:

The absolute error is the the difference in the measured value and the actual value of a quantity.

Here the actual value is 5.0000 grams

The measured value is 5.001 grams

Absolute error

5.001 - 5.000\\= 0.001

Percent error

= \frac{AE}{AV}

Where AE stands for absolute error and AV stands for absolute value.

= \frac{0.001}{5.000} * 100\\

= 0.02 %

5 0
3 years ago
Determine the density of nh3 gas at 435k and 1.00atm
goldenfox [79]
We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:

PV=nRT 

We manipulate this equation to give us an expression which will correspond to density. We do as follows:

PV= nRT
P/RT = n/V where n = m/MM
P(MM) /RT = m/V = density
Density = 1.00 (17.03) / 0.08206 (435)
Density = 0.48 g / L

5 0
3 years ago
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