All categories

3 years ago

If you move a substance from one container to another and its volume changes substance is?

Chemistry

2 answers:

My name is Ann [436]3 years ago

6 0

If you move a substance from one container to another and its volume changes, then the substance is gas that is right

astra-53 [7]3 years ago

5 0

If you move a substance from one container to another and its volume changes substances is gas.

You might be interested in

How is science used on a daily basis give 3 reasons how

goldenfox [79]

1-Autonomy: Our desire to direct our own lives. In short: “You probably want to do something interesting, let me get out of your way!”
2-Mastery: Our urge to get better at stuff.
3-Purpose: The feeling and intention that we can make a difference in the world.

7 0

3 years ago

What is the purpose of sodium and chloride ions in the exoeruent?

Klio2033 [76]

What is the exoeruent. Searched it up on google and only came up with two search results. None related to chemistry

5 0

3 years ago

Mengapa garam NaNO2 dapat membirukan kertas lakmus merah? Jelaskan dengan reaksi kimianya!

Reika [66]

Can't understand this. English Please! :) :)

8 0

3 years ago

PLEASE HELP ASAP!

egoroff_w [7]

Answer:

Lithium fluoride i think but I am not really sure

But it should be Lithium fluoride

Explanation: that's because neighter boron nor nitrogen contains water

3 0

2 years ago

When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°

dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.30^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant =

m= molality = $\frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579$

$8.30^0C=1\times K_f\times 0.579$

$K_f=14.3^0C/m$

Let Mass of solute (KBr) = x g

$8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}$

$x=58.2g$

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

7 0

2 years ago