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Alona [7]
2 years ago
9

Competitive inhibition occurs when a

Chemistry
2 answers:
Aleksandr-060686 [28]2 years ago
6 0
The answer to your question is C.
ioda2 years ago
3 0

Answer:

Competitive inhibition occurs when a molecule binds to an enzyme in the active site and prevents the substrate from binding. (C)

Explanation:

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The specific rotation of (S)-2-butanol is +13.5. If 0.119 g of its enantiomer is dissolved in 10.0 mL of ethanol and
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+15.8°

Explanation:

The formula for the observed rotation (α) of an optically active sample is

α = [α]<em>lc </em>

where

<em>l</em> = the cell path length in decimetres

<em>c</em> = the concentration in units of g/100 mL

[α] = the specific rotation in degrees  

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c = \frac{\text{0.119 g}}{\text{10.0 mL}} \times \frac{10 }{10 } =\frac{\text{1.19 g}}{\text{100 mL}}

2. Calculate the observed rotation

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3 years ago
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The initial pressure of a mixture of C6H6 and an excess of H2 in a rigid vessel is 1.21 atm. A catalyst is introduced. After the
KengaRu [80]

Answer:

mole fraction of C6H6 = 0.613 atm

Explanation:

The equation for this reaction is :

          C_6H_6 _{(g)} + 3H_2_{(g)} \to C_6H_{12}_{(g)}

Initial      P₁            P₂             0

Final        0           P₂ -P₁/2      P₁

After completion of the reaction;

P₁  +  P₂  = 1.21 atm                    ----- (1)

P₂  -  P₁/2 +  P₁ = 0.839 atm

P₂ + P₁/2 = 0.839 atm          ----- (2)

Subtracting (2) from (1); we have:

P₁/2 = 0.371

P₁ = 0.742 atm

From(1)

P₁  +  P₂  = 1.21 atm

0.742 atm + P₂  = 1.21 atm

P₂  = 1.21 atm - 0.742 atm

P₂  = 0.468 atm

Thus, the partial pressure of C6H6 = 0.742 atm

∴

Partial pressure = Total pressure × mole fraction of C6H6

mole fraction of C6H6 = Partial pressure /  Total pressure

mole fraction of C6H6 = 0.742 atm / 1.21 atm

mole fraction of C6H6 = 0.613 atm

5 0
3 years ago
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