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Alona [7]
2 years ago
9

Competitive inhibition occurs when a

Chemistry
2 answers:
Aleksandr-060686 [28]2 years ago
6 0
The answer to your question is C.
ioda2 years ago
3 0

Answer:

Competitive inhibition occurs when a molecule binds to an enzyme in the active site and prevents the substrate from binding. (C)

Explanation:

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What would happen if your experimental value of water was too low or too high?
spin [16.1K]
Your experimental value would not be accurate

8 0
3 years ago
The equation for density, d, is
ss7ja [257]

<u>Answer:</u> The density of substance is 3.38g/cm^3

<u>Explanation:</u>

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Mass of substance = 61.6 g

Volume of substance = 18.2cm^3

Putting values in above equation, we get:

\text{Density of substance}=\frac{61.6g}{18.2cm^3}\\\\\text{Density of substance}=3.38g/cm^3

Hence, the density of substance is 3.38g/cm^3

8 0
3 years ago
Given the reaction agi(s) ↔ ag+(aq) + i-(aq) solution equilibrium is reached in the system when
Julli [10]
Missing question:
1) the rate of dissolving reaches zero 
<span>2) the rate of crystallization reaches zero </span>
3) the rate of dissolving is zero and the rate of crystallization is greater than zero.
<span>4) both the rate of dissolving and the rate of crystallization are equal and greater than zero.
</span>
Answer is: 4) both the rate of dissolving and the rate of crystallization are equal and greater than zero.
Silver chloride (AgCl) dissolves and form silver and chlorine ions, in the same time silver and chlorine ions crystallizate and form solid salt silver chloride.
In equilibrium rates of dissolvinf and crysallization and concentration of ions do not change.
7 0
3 years ago
Hi! Which of the following decreases kinetic energy of solvent molecules? ( I need this handed in quickly!)
Black_prince [1.1K]

Answer:

c

Explanation:

4 0
3 years ago
Ammonia can be produced in the laboratory by heating ammonium chloride
AnnyKZ [126]

Answer:

Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

Mass of ammonia produced = ?

Solution:

2NH₄Cl   +  Ca(OH)₂     →    CaCl₂ + 2NH₃ + 2H₂O

Number of moles of NH₄Cl:

Number of moles = mass/molar mass

Number of moles = 8.939 g / 53.5 g/mol

Number of moles = 0.17 mol

Number of moles of Ca(OH)₂ :

Number of moles = mass/molar mass

Number of moles = 7.48 g / 74.1 g/mol

Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

                      NH₄Cl          :          NH₃

                          2              :           2

                         0.17          :          0.17

                   Ca(OH)₂         :          NH₃

                        1                :           2

                    0.10              :          2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0
3 years ago
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