Answer:
ΔE(work)= 692 Kj/mole e⁻ = 4.32 x 10²⁴ eV/mole e⁻
Explanation:
ΔE = hc/λ = (6.63 x 10⁻³⁴j·s)(2.99792 x 10⁸m/s)/(1.73 x 10⁻⁷m) = 1.15 x 10⁻¹⁸j/e⁻ x 6.023 x 10²³ e⁻/mole = 691,999 j/mole e⁻ = 692 Kj/mole e⁻ x 6.24 x 10²¹ eV/KJ = 4.32 x 10²⁴ eV/mole e⁻
Answer:
1.6605 × 10⁻²³ g / atom , 9.99 amu
Explanation:
Atoms present in 1 mole = 6.022 × 10²³ atoms
Given that
Moles of common Eastern mole = 8.3 moles
So,
Atoms in 8.3 moles are:
8.3 moles = 6.022 × 10²³ × 8.3 atoms
Also,
Average mass = Mass of the sample / Number of atoms
Mass of sample = 83 g
Average mass = 83 g / 6.022 × 10²³ × 8.3 atoms = 1.6605 × 10⁻²³ g / atom
In amu :
1 amu = 1.66 × 10⁻²⁴ g / atom
So,
Average mass = 1.6605 × 10⁻²³ / 1.66 × 10⁻²⁴ amu = 9.99 amu
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Answer: helium(He)
Explanation: Helium has only 2 electrons in the outermost energy level, but all of the other elements in its column have eight.
