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Juli2301 [7.4K]

3 years ago

15

What would decrease the resistance of wires carrying an electric current

2 answers:

Lostsunrise [7]3 years ago

6 0

Answer:

A. shorter wires

Explanation:

Murljashka [212]3 years ago

3 0

I believe the answer is A. shorter wires

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What is the direction of the electric field at the corner? What is the direction of the electric field at the corner? along the

ehidna [41]

Answer:

jsjsj isso isso isms sim

Explanation:

jjed djdn djms disse sjsm disse mism

7 0

3 years ago

Find the net work W done on the particle by the external forces during the motion of the particle in terms of the initial and fi

steposvetlana [31]

Answer:

$W=K_f-K_i$

Explanation:

The work done on a particle by external forces is defined as:

$W=\int\limits^{r_f}_{r_i} {F\cdot dr} \,$

According to Newton's second law $F=ma$ . Thus:

$W=\int\limits^{r_f}_{r_i}{ma\cdot dr} \,\\$

Acceleration is defined as the derivative of the speed with respect to time:

$W=m\int\limits^{r_f}_{r_i}{\frac{dv}{dt}\cdot dr} \,\\\\W=m\int\limits^{r_f}_{r_i}{dv \cdot \frac{dr}{dt}} \,$

Speed is defined as the derivative of the position with respect to time:

$W=m\int\limits^{v_f}_{v_i} v \cdot dv \,$

Kinetic energy is defined as $K=\frac{mv^2}{2}$ :

$W=m\frac{v_f^2}{2}-m\frac{v_i^2}{2}\\W=K_f-K_i$

3 0

3 years ago

A thin walled spherical shell is rolling on a surface. What

ExtremeBDS [4]

Answer:

$=\frac{1/3}{5/6} = 0.4$

Explanation:

Moment of inertia of given shell $= \frac{2}{3} MR^2$

where

M represent sphere mass

R -sphere radius

we know linear speed is given as $v = r\omega$

translational $K.E = \frac{1}{2} mv^2 = \frac{1}{2} m(r\omega)^2$

rotational $K.E = \frac{1}{2} I \omega^2 = \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

total kinetic energy will be

$K.E = \frac{1}{2} m(r\omega)^2 + \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

$K.E =\frac{5}{6} MR^2 \omega^2$

fraction of rotaional to total K.E

$=\frac{1/3}{5/6} = 0.4$

8 0

3 years ago

You are playing right field for the baseball team. Your team is up by one run in the botton of the last inning of the game when

VARVARA [1.3K]

Answer:

The correct response is "No". The further explanation is given below.

Explanation:

The given values are:

Angle

$\theta = 30^{\circ}$

Distance

d = 20 m

Speed

s = 8.0 m/s

Now,

⇒ $y(t) = \frac{1}{2}\times a\times t^2 + v0\times t\times (sin \theta)$

$0 = -4.9t^2 + v0\times t\times (sin 30)$

$x = v0\times (cos \theta)\times t$

$65 = v0\times (cos 30)\times t$

$v0\times t = \frac{65}{Cos30}$

$0 = -4.9t^2 + 65\times \frac{sin30}{cos30}$

$t = 2.767 \ sec$

So,

⇒ $d = r\times t$

$20 = 8\times t$

$t=2.5 \ sec$

Therefore, 2.5 < 2.767, so it won't get there.

6 0

3 years ago

When an object moves at a constant speed in a circular path, it is said to be in uniform _________ motion?

Snezhnost [94]

It is said to be moving in uniform CIRCULAR motion. Hope this helps. Thanks

7 0

3 years ago

Read 2 more answers