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Juli2301 [7.4K]
3 years ago
15

What would decrease the resistance of wires carrying an electric current

Physics
2 answers:
Lostsunrise [7]3 years ago
6 0

Answer:

A. shorter wires

Explanation:

Murljashka [212]3 years ago
3 0
I believe the answer is A. shorter wires


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A charge of −20 µC is distributed uniformly over the surface of a spherical conductor of radius 11.0 cm. Determine the electric
Alex73 [517]

Answer:

(a) -6.76\times 10^{12}\ N/C

(b) -1.352\times 10^{13}\ N/C

(c) -7.2\times 10^{11}\ N/C

Explanation:

(a)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 5 cm = 0.05 m

Coulomb's constant (k) = 9\times 10^{9}\ Nm^2/C^2

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

E=(\frac{kQ}{R^3})r

Plug in the given values and solve for 'E'. This gives,

E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.05\\\\E_{in}=-1.352\times 10^{14}\times 0.05\\\\E_{in}=-6.76\times 10^{12}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

(b)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 10 cm = 0.10 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

E=(\frac{kQ}{R^3})r

Plug in the given values and solve for 'E'. This gives,

E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.10\\\\E_{in}=-1.352\times 10^{14}\times 0.10\\\\E_{in}=-1.352\times 10^{13}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

(c)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 50 cm = 0.50 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r > R' from the center of sphere is given as:

E=\dfrac{kQ}{r^2}

Plug in the given values and solve for 'E'. This gives,

E_{out}=(\frac{9\times 10^{9}\times -20}{(0.50)^2})\\\\E_{out}=-7.2\times 10^{11}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

8 0
4 years ago
What are 5 ways to conserve energy at school?
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Your friend won the race that you were both running. Instead of being gracious, your friend made fun of you for losing, and now
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Negative peer influence
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Where is the independent variable usually located in a scientific table? First column Second column Third through fifth columns
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Explanation:

On the horizontal side left side

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It depends on what skateboard. It will stop mainly because some  skateboards need a hill or curvy platform to function.

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