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tensa zangetsu [6.8K]
2 years ago
10

According to the graph, during which time interval are the particles in the air slowing down?

Physics
2 answers:
kenny6666 [7]2 years ago
4 0
Answer b like the last time should be it
eimsori [14]2 years ago
3 0
Answer should be b 6:00pm to 12:00 am
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A train of 150 m length is going toward north direction at a speed of 10 ms–1 and a parrot is flying towards south direction par
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Answer:

10ms

Explanation:

The bird must travel the length of the train (150m), with a combined speed of 15m/s this means it will take 10s to cross an accumulated 150ms.

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Karyn is a zookeeper who takes care of baboons. Each day, Karyn writes down how the baboons eat, play, sleep, and wash. She revi
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The statement which explains why Karyn's approach is an investigation instead because she is not attempting to change outcomes.

<h3>What is Investigation?</h3>

This is defined as the systematic study of a subject topic and involves various forms of observation.

It however doesn't involve measuring variable as the outcomes aren't changed but only recorded.

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How many electrons do alkali metals have in their outer shell?
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The outer shell can hold 1 electron
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3 years ago
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If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the earth's surface
Alecsey [184]

Answer: h = 3R

Explanation:

Using the law of conservation of energy,

Total energy at the beginning of the launch would be equal to total energy at any point.

kinetic energy + gravitational potential energy = constant

Initial energy of the projectile =\frac{1}{2}mv_e^2-\frac{GMm}{R}... (1)

where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.

escape velocity, v_e=\sqrt{\frac{2GM}{R}}

Total energy at height h above the Earth where speed of the projectile is half the escape velocity:

\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} ...(2)

(1)=(2)

⇒\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} = \frac{1}{2}mv_e^2-\frac{GMm}{R}

⇒G\frac{Mm}{R}-G\frac{Mm}{R+h}= \frac{1}{2}m \frac{3}{4}v_e^2 =\frac{1}{2}m \frac{3}{4} (\sqrt{\frac{2GM}{R}})^2

⇒\frac{GM(R+h-R)}{R(R+h)} = \frac{3}{4}(\frac{GM}{R})

⇒\frac{h}{R+h} = \frac{3}{4}

⇒h = 3R

Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.  

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3 years ago
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When Jacob bats a baseball with a net force of 4.719 N, it accelerates 33 m/s2. What is the mass of the baseball?
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Answer:

its 24

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