Answer:
a)v=15.83 m/s
b)v=14.89 m/s
Explanation:
a)
In y direction
Given that h=35 m and initial velocity is zero.
So
t=2.67 sec
It means that rock hit water after 2.61 sec.
Given that player hears after 2.83 sec.
Δt=2.83 - 2.67 s
Δt=0.16 sec
So distance travel by sound wave
d= C x Δt
C= 343 m/s
d= 343 x 0.16
d=54.88 m
From diagram
x=42.27 m
Now
x = v x t
v=42.27/2.67
v=15.83 m/s
b)
Now sound speed have been changed
So new d
d=331 x 0.16
d=52.96 m
New x
x=39.75
So new velocity v
v=x/t
v=39.75/2.67
v=14.89 m/s
You will use the Pythagorean Theorem to solve it.
c^2 = a^2 + b^2
c^2 = (1.5)^2 + (2)^2
c^2 = 6.25
c = square root of 6.25
c = 2.5
I hope this helps!
Answer:
θ = 33.8
a = 3.42 m/s²
Explanation:
given data
mass m = 2 kg
coefficient of static friction μs = 0.67
coefficient of kinetic friction μk = 0.25
solution
when block start slide
N = mg cosθ .............1
fs = mg sinθ ...............2
now we divide equation 2 by equation 1 we get
= tanθ
put here value we get
tan θ = 0.67
θ = 33.8
and
when block will slide then we apply newton 2nd law
mg sinθ - fk = ma ...............3
here fk = μk N = μk mg cosθ
so from equation 3 we get
mg sinθ - μk mg cosθ = ma
so a will be
a = (sinθ - μk cosθ)g
put here value and we get
a = (sin33.8 - 0.25 cos33.8) 9.8
a = 3.42 m/s²
If im correct the answer is gravity
and wind resistance if you lift it fast
~~~hope this helps~~~
~~davatar~~
Answer:
The movement of Tectonic plates.
Explanation: