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2 years ago

Alkaline batteries are non-rechargeable. Why do alkaline batteries eventually stop working?

Chemistry

1 answer:

scoray [572]2 years ago

4 0

Answer:

Alkaline batteries stop working when all of the manganese dioxide has been converted.

Explanation: Hope it helps you :)))

Have a good day

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A fossil was analyzed and determined to have a carbon-14 level that is 70 % that of living organisms. The half-life of C-14 is 5

Citrus2011 [14]

Answer: 2948

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{5730}=1.21\times 10^{-4}years^{-1}$

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}years^{-1}$

t = age of sample = ?

a = let initial amount of the reactant = 100

a - x = amount left after decay process = $\frac{70}{100}\times 100=70$

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{100}{70}$

$t=2948years$

Thus the fossil is 2948 years old.

5 0

3 years ago

Definition of phosphoric acid

miss Akunina [59]

Phosphoric acid is an acid used in fertilizers and soaps.

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3 years ago

A gas has a volume of 3.00 L at 65.0 C. The same gas has a volume of 11.4 L at 105 C and 1725 mmHg. What was the original pressu

velikii [3]

Mm yes diirjrjejekeiejebenwkowe

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3 years ago

How does helium form (5-8) sentences

Firlakuza [10]

On Earth it is relatively rare—5.2 ppm by volume in the atmosphere. Most terrestrial helium present today is created by the natural radioactive decay of heavy radioactive elements (thorium and uranium, although there are other examples), as the alpha particles emitted by such decays consist of helium-4 nuclei.

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3 years ago

Amantadine is effective in preventing infections caused by the influenza A virus and in treating established illnesses. It is th

Sliva [168]

Answer:

See image attached

Explanation:

The full reaction mechanism of step 1 was obtained from Bartleby and attached to this answer. The steps involved in the reaction are:

1) Loss of Br- and formation of a carbocation

2) Attack of CH3CN on the carbocation

4) Formation of a quaternary nitrogen intermediate

5) Attack of water on the quaternary nitrogen intermediate

6) Loss of the water molecule

5) Formation of the amide product

i) sodium hydroxide

ii) HCl

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3 years ago