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barxatty [35]
3 years ago
14

A car of weight 11000 N moves with constant velocity along a horizontal road.A driving force of 5000 N acts on the car what is t

he force opposing the motion of the car
Physics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

5000 N

Explanation:

Since F - f = ma, where F = driving force = 5000 N, f = opposing force, m = mass of car and a = acceleration of car.

Since the car is moving with constant velocity, a = 0.

So, F - f = ma

F - f = m(0)

F - f = 0

F = f.

Since F = 5000 N and F = f, f = 5000 N.

So, the opposing force is 5000 N

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Maximum speed of the child as she swings is  2.23 m/s.

<h3>Step by Step Calculation:</h3>

T=3.3 s is the oscillation's time period.

The swing's greatest angle is 25° (max).

The swing's bottom will have the following kinetic energy:

k=12mv2...........(1)

The mass in this situation is m, and the speed is v.

The potential energy change is expressed as,

∆U=mgL1-cosθmax...............(2)

Here, L is a string's length and g is the acceleration caused by gravity. L is given as,

L=gT24π2

Combine equation (1) with (2)

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22.33 m/s, 22.31 s22.31 cos25°

Therefore, the child's top speed is 2.23 m/s.

<h3>What is Oscillation ?</h3>
  • The process of any quantity or measure fluctuating repeatedly about its equilibrium value in time is known as oscillation.
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To learn more about Oscillation refer to:

brainly.com/question/28312746

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