3, A 4kg block is pushed 2m at an acceleration of 0.2m/s square up a vertical wall by a constant force F applied at an angle of
1 answer:
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Answer:
V = - 0.5 [m/s]
Explanation:
In order to solve this problem, we must use the principle of relative speeds. This is for an observer who is on the edge of the river he can see how the river moves to the left and the woman tries to move to the right but can not since:
That is, the person sees how the woman moves to the left but with avelocity of 0.5 [m/s] to the left
Answer:
6.0 m/s
Explanation:
According to the law of conservation of energy, the total mechanical energy (potential, PE, + kinetic, KE) of the athlete must be conserved.
Therefore, we can write:
or
where:
m is the mass of the athlete
u is the initial speed of the athlete (at the bottom)
0 is the initial potential energy of the athlete (at the bottom)
v = 0.80 m/s is the final speed of the athlete (at the top)
is the acceleration due to gravity
h = 1.80 m is the final height of the athlete (at the top)
Solving the equation for u, we find the initial speed at which the athlete must jump:
Answer:
Explanation:
Given that:
p = magnitude of charge on a proton =
k = Boltzmann constant =
r = distance between the two carbon nuclei = 1.00 nm =
Since a carbon nucleus contains 6 protons.
So, charge on a carbon nucleus is
We know that the electric potential energy between two charges q and Q separated by a distance r is given by:
So, the potential energy between the two nuclei of carbon is as below:
Hence, the energy stored between two nuclei of carbon is .