Question

3, A 4kg block is pushed 2m at an acceleration of 0.2m/s square up a vertical wall by a constant force F applied at an angle of 37° with the horizontal, as shown. If the cofficient of kinetic friction between the block and the wall is 0.30. Find the work done by the applied force the frictional force.​

Answer 1

The work done by the applied force on the block against the frictional force is 15.75 J.

Work done by the applied force

The work done by the applied force is calculated as follows;

W = Fd

F - Ff = ma

where;

• F is applied force
• Ff is frictional force

Fcos(37) - μmgsin(37) = ma

Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)

0.799F - 7.077 = 0.8

F = 9.86 N

W = Fdcosθ

W = 9.86 x 2 x cos(37)

W = 15.75 J

Thus, the work done by the applied force on the block against the frictional force is 15.75 J.

Learn more about work done here: brainly.com/question/25573309

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