Answer:
d. x < 9.02 or x > 9.48 because |x − 9.25| > 0.23
Step-by-step explanation:
Given,
The standard weight of the pack = 9.25 oz,
The pack must weigh within 0.23 oz of the target weight to be accepted.
i.e. if x represents the weight of the pack,
If x > 9.25 oz
then x - 0.925 ≤ 0.23 ......(1)
if x < 9.25
then 9.25 - x ≤ 0.23
⇒ -(x-9.25) ≤ 0.23 .......(2)
From equation (1) and (2),
The accepted range of mass is,
|x-9.25| ≤ 0.23
Hence, the rejected range mass would be,
|x-9.25| > 0.23
⇒ x - 9.25 > 0.23 or -x + 9.25 < 0.23
⇒ x > 0.23 + 9.25 or -x > 0.23 - 9.25
⇒ x > 9.48 or - x > −9.02
⇒ x > 9.48 or x < 9.02
