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Ilya [14]
3 years ago
6

-Boston tea party-

Physics
1 answer:
lisov135 [29]3 years ago
4 0

Answer: The Boston Tea Party was a political protest that occurred on December 16, 1773, at Griffin’s Wharf in Boston, Massachusetts. American colonists, frustrated and angry at Britain for imposing “taxation without representation,” dumped 342 chests of tea, imported by the British East India Company into the harbor. The event was the first major act of defiance to British rule over the colonists. It showed Great Britain that Americans wouldn’t take taxation and tyranny sitting down, and rallied American patriots across the 13 colonies to fight for independence.

Explanation: brainlest please

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The normal eye, myopic eye and old age
yanalaym [24]

Answer:

1)    f’₀ / f = 1.10, the relationship between the focal length (f'₀) and the distance to the retina (image) is given by the constructor's equation

2) the two diameters have the same order of magnitude and are very close to each other

Explanation:

You have some problems in the writing of your exercise, we will try to answer.

1) The equation to be used in geometric optics is the constructor equation

          \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where p and q are the distance to the object and the image, respectively, f is the focal length

* For the normal eye and with presbyopia

the object is at infinity (p = inf) and the image is on the retina (q = 15 mm = 1.5 cm)

        \frac{1}{f'_o} = 1/ inf + \frac{1}{1.5}

        f'₀ = 1.5 cm

this is the focal length for this type of eye

* Eye with myopia

the distance to the object is p = 15 cm the distance to the image that is on the retina is q = 1.5 cm

           1 / f = 1/15 + 1 / 1.5

           1 / f = 0.733

            f = 1.36 cm

this is the focal length for the myopic eye.

In general, the two focal lengths are related

         f’₀ / f = 1.5 / 1.36

         f’₀ / f = 1.10

The question of the relationship between the focal length (f'₀) and the distance to the retina (image) is given by the constructor's equation

2) For this second part we have a diffraction problem, the point diameter corresponds to the first zero of the diffraction pattern that is given by the expression for a linear slit

          a sin θ= m λ

the first zero occurs for m = 1, as the angles are very small

          tan θ = y / f = sin θ / cos θ

for some very small the cosine is 1

          sin θ = y / f

where f is the distance of the lens (eye)

           y / f = lam / a

in the case of the eye we have a circular slit, therefore the system must be solved in polar coordinates, giving a numerical factor

           y / f = 1.22 λ / D

           y = 1.22 λ f / D

where D is the diameter of the eye

          D = 2R₀

          D = 2 0.1

          D = 0.2 cm

           

the eye has its highest sensitivity for lam = 550 10⁻⁹ m (green light), let's use this wavelength for the calculation

         

* normal eye

the focal length of the normal eye can be accommodated to give a focus on the immobile retian, so let's use the constructor equation

      \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

sustitute

       \frac{1}{f} = \frac{1}{25} + \frac{1}{1.5}

       \frac{1}{f}= 0.7066

        f = 1.415 cm

therefore the diffraction is

        y = 1.22  550 10⁻⁹  1.415  / 0.2

        y = 4.75 10⁻⁶ m

this is the radius, the diffraction diameter is

       d = 2y

       d_normal = 9.49 10⁻⁶ m

* myopic eye

In the statement they indicate that the distance to the object is p = 15 cm, the retina is at the same distance, it does not move, q = 1.5 cm

       \frac{1}{f} = \frac{1}{15} + \frac{1}{ 1.5}

        \frac{1}{f}= 0.733

         f = 1.36 cm

diffraction is

        y = 1.22 550 10-9 1.36 10-2 / 0.2 10--2

        y = 4.56 10-6 m

the diffraction diameter is

        d_myope = 2y

         d_myope = 9.16 10-6 m

         \frac{d_{normal}}{d_{myope}} = 9.49 /9.16

        \frac{d_{normal}}{d_{myope}} =  1.04

we can see that the two diameters have the same order of magnitude and are very close to each other

8 0
3 years ago
The sun's core _____. A) is made of solid helium B) makes up most of the sun's size C) creates energy by fusing hydrogen into he
VashaNatasha [74]
I think the correct answer is C
6 0
3 years ago
Read 2 more answers
How long will it take this wave to travel 3000 m in the x-direction?
REY [17]
2.4 secs I think



?????????????????????????
5 0
3 years ago
In a certain breed of cats, having black hair is the result of two dominant alleles for hair color (HH). The heterozygous genoty
valina [46]

Answer:

The punnet chart indicate the cross between a black cat and a spotted cat.

Explanation:

As the punnet chart was not given with the question, the question is searched and found online which is as attached herewith.

As seen from the punned table the column head has two capital H which indicate that the cat is a black cat.

White the row heads indicate a Capital and a small h thus this is a spotted cat

Thus the punnet chart indicate the cross between a black cat and a spotted cat.

6 0
2 years ago
Read 2 more answers
How does a perspective drawing differ from an isometric drawing of the same object? when would you use a perspective view in lie
klemol [59]
<span>The quick way to visualize this is to compare isometric and perspective drawings of a cube. In the isometric drawing, all the edges of the cube would be parallel in sets of four. In the perspective drawing, the edges would taper towards one or more vanishing points. The isometric drawing, being easier to construct, perserving all scales and dimensions, is the preferred method for mechanical drawings, and are practical for use in the shop. The perspective drawing, which are trickier to draw properly, and does not preserve scales and dimensions, is the preferred method for architectural drawings, because they illustrate what the eye actually sees.</span>
7 0
3 years ago
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