-Boston tea party-

1 answer:

4 0

Answer: The Boston Tea Party was a political protest that occurred on December 16, 1773, at Griffin’s Wharf in Boston, Massachusetts. American colonists, frustrated and angry at Britain for imposing “taxation without representation,” dumped 342 chests of tea, imported by the British East India Company into the harbor. The event was the first major act of defiance to British rule over the colonists. It showed Great Britain that Americans wouldn’t take taxation and tyranny sitting down, and rallied American patriots across the 13 colonies to fight for independence.

Explanation: brainlest please

You might be interested in

The sense of smell helps protect us against danger. Explain why.

atroni [7]

Well we can always smell things like if food smells bad or if we smell something we have to know whether that smell is good or bad. You could be able to smell animals that are dangerous. Or animal droppings, to know what animal it is if you are in danger.

6 0

3 years ago

Consult Conceptual Example 9 in preparation for this problem. Interactive LearningWare 6.3 also provides useful background. The

Alex73 [517]

Answer:

11.56066 m/s

Explanation:

m = Mass of person

v = Velocity of person = 13.4 m/s

g = Acceleration due to gravity = 9.81 m/s²

v' = Velocity of the person in the second

The kinetic and potential energy will balance each other at the surface

$\dfrac{1}{2}mv^2=mgh\\\Rightarrow h=\dfrac{v^2}{2g}\\\Rightarrow h=\dfrac{13.4^2}{2\times 9.81}\\\Rightarrow h=9.15188\ m$

Height of the cliff is 9.15188 m

Let height of the fall be h' = 2.34 m

$\dfrac{1}{2}mv'^2+mgh'=mgh\\\Rightarrow v'=\sqrt{2g(h-h')}\\\Rightarrow v'=\sqrt{2\times 9.81(9.15188-2.34)}\\\Rightarrow v'=11.56066\ m/s$

The speed of the person is 11.56066 m/s

3 0

3 years ago

A roulette wheel with a 1.0m radius reaches a maximum angular speed of 18 rad/s before it stops 35 revolutions ( 220 rad ) after

Alex17521 [72]

Max ang. speed(u) = 18 rad/s
final ang. speed(v) = 0
ang. displacement(s) = 220 rad

ang. acceleration = (v^2 - u^2)/2s = -18^2 / 2*220 = -0.7364 rad/s^2

v = u +at
0 = 18 - 0.7364t
t = 18/0.7364
t = 24.44 seconds

4 0

3 years ago

Two point charges are placed on the x axis as follows: charge q1=+3.75nc is located at x=0.205m and charge q2=−5.60 nc is at x=+

Mademuasel [1]

I might have did mistake with calculations but this is how you should do.