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4 years ago

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Any Help??? Dued before 2:30pm and it's 9:30am by me... so please take yuh time and ans.... jus ans 1 if you want... This is for

course marks.... I appreciate all efforts❤

1 answer:

Kryger [21]4 years ago

5 0

Answer:

The methodology employed by Galileo contributed to the development of Physics by find moons of Jupiter. (I think)

sorry if it's wrong

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Help me please I’m begging u!!

Yakvenalex [24]

The speed of a wave, c, is given by the length of the wave, λ, times the frequency (times per second a cycle passes). Since frequency has units of inverse seconds, the units will then be m/s as we expect.
$c= \lambda f=2m * 140Hz=280m/s$

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3 years ago

Lana71 [14]

Answer:

true

Explanation:

Some factors of heart disease cannot be controlled. A diet rich in high-density lipoproteins (HDLs) can help cleanse and open arteries that are clogged with plaque. Exercise can help prevent heart disease but once you've had a heart attack, it's too late for exercise to help you.

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2 years ago

Reena has rolled down her toy car through a ramp. When she increases the height of the ramp (10 cm ) the car has travelled 5 met

Stolb23 [73]

Answer:

As she raises the height of the ramp, the speed of the toy car decreases.

Explanation:

Speed is the ratio of the distance traveled by an object to the time taken.

i.e speed = $\frac{distance}{time}$

From the given question, it would be observed that:

i. when the height of the ramp was 10 cm, the car traveled 5 meters.

ii. when the height of the ramp was increased to 13 cm, the car traveled 6 meters.

Therefore, an increase in the height of the ramp causes a decrease in the speed of the toy car so that the distance traveled per unit time increases. Showing that there is an inverse relationship between the height of the ramp and the speed of the toy car.

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3 years ago

What is population compostion<br>

Andrej [43]

Answer :

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3 years ago

An object with mass of 4kg is thrown with initial velocity of 20m/s from point A and follows the track of ABCD.

soldier1979 [14.2K]

<u>The distance of the length YD is 3.57m, the velocity of the object at point D is 27m/s and the time required for the object to reach the ground is 0.17s</u>

Data given;

Mass = 4kg

Initial velocity = 20m/s

length CD = 5m (from the image given)

a)

<h3>Determine The Length of YD</h3>

$YD=CDsin$ θ = $5sin45=\frac{5}{\sqrt{2} } = 3.57m$

b)

<h3>The velocity of the object at point D</h3>

The change in kinetic energy is given as

Δ in kinetic energy = Δ in potential energy + work done by friction

K.E - 1/2m $v^2$ = mgh $_1$ - mgh $_2$ + (-μmg.x)

K.E = mg(50 - 3.57) + (-mg(0.3*100) + 1/2 m $v^2$

$\frac{1}{2}mv^2_f=mg(46.43)-mg(30)+\frac{1}{2} m(400)\\\\v^2_f=20(16.43)+400\\v^2_f=728.6\\v=\sqrt{728.6} \\v_f=26.99 = 27m/s$

The velocity of the object at D with a distance of 5m.

c)

<h3>The the required for the object to reach ground</h3>

The velocity of the object in the y-axis is

$v_y=vsin45=19.09$

Acceleration in y-axis = 9.8

Height = 3.57m

h = $ut+\frac{1}{2}at^2$

$3.57=19.28(t)+\frac{1}{2}(9.8)t^2\\3.57=19.28t+4.9t^2\\4.9t^2+19.28t-3.57=0\\a=4.9, b=19.28, c= -3.57\\t=\frac{-19.28+\sqrt{(19.28)^2-4(4.9)(-3.57)} }{(2*4.9)} \\t=\frac{-19.28+21.02}{9.8}$

Taking the positive value

$\frac{-19.28+21.02}{9.8}=0.17s$

The time required for the object to reach ground is 0.17s

From the calculations above,<u> the distance YD is 3.57m, the velocity of the object at point D is 27m/s and the time required for the object to reach ground is 0.17s</u>

Learn more on projectile motion here;

brainly.com/question/1130127

<h3 />

5 0

3 years ago