Any Help??? Dued before 2:30pm and it's 9:30am by me... so please take yuh time and ans.... jus ans 1 if you want... This is for
course marks.... I appreciate all efforts❤
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(a) The skater covers a distance of S=50 m in a time of t=12.1 s, so its average speed is the ratio between the distance covered and the time taken:
(b) The initial speed of the skater is
while the final speed is
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
(c) The initial speed of the skater is
while the final speed is
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
from which we find
where the negative sign means it is a deceleration.
(b) The initial speed of the skater is
while the final speed is
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
(c) The initial speed of the skater is
while the final speed is
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
from which we find
where the negative sign means it is a deceleration.