Sara and Sam went for a two-hour drive. According to the graph, between .75 hours and 1.25 hours into their trip, they
2 answers:
I have attached a screenshot with the complete question.
Answer:
were not moving since there was no change in position
Explanation:
In the given graph, we have the x-axis showing the time they walked and the y-axis showing the distance they moved.
In the interval between 0.75 hours and 1.25 hours, we can note that the distance is remaining constant at 30 km.
This means that during this interval, their distance did not change which implies that they were not walking.
Hope this helps :)
Answer:
were not moving since there was no change in position
Explanation:
In the given graph, we have the x-axis showing the time they walked and the y-axis showing the distance they moved.
In the interval between 0.75 hours and 1.25 hours, we can note that the distance is remaining constant at 30 km.
This means that during this interval, their distance did not change which implies that they were not walking.
Hope this helps :)
You might be interested in
Answer:
0.0928km/min (4dp)
Explanation:
To find the jogger's speed in km per minute, we just need to divide the number of km jogged by the time in minutes it took to jog that distance. This will give us the distance they jogged every minute which is their speed.
4km in 32 minutes:
4/32 = 0.125km/min
2km in 22 minutes:
2/22 = 0.091 (3dp)km/min
1km in 16 minutes:
0.0625km/min
Now to find the average speed of these 3 speeds, we just add them all together and divide by how many values there are (3 values).
Average (mean) =
Average = 0.2785/3
Average speed of jogger = 0.0928 (4dp) km/min
Hope this helped!
The displacement vector (SI units) is
![\vec{r} =At\hat{i}+A[t^{3}-6t^{2}]\hat{j}](https://tex.z-dn.net/?f=%5Cvec%7Br%7D%20%3DAt%5Chat%7Bi%7D%2BA%5Bt%5E%7B3%7D-6t%5E%7B2%7D%5D%5Chat%7Bj%7D)
The speed is a scalar quantity. Its magnitude is
Answer: At√(t⁴ - 12t³ + 36t² + 1)
The speed is a scalar quantity. Its magnitude is
Answer: At√(t⁴ - 12t³ + 36t² + 1)
Answer:
D. Top is emission; bottom absorption.
Explanation:
Emission and spectrum of elements are due to the element absorbing or emitting wavelength of e-m energy. Elementary particles of elements can absorb energy from a ground state to enter an excited state, creating an absorption spectrum, or they can lose energy and fall back to a lower energy state, creating an emission spectrum. A simple rule to differentiate between an emission and an absorption spectrum is that: "all absorbed wavelength is emitted, but not all emitted wavelength is absorbed."
From the image, the lines indicates wavelengths. We can see that all of the wavelengths of the bottom absorption spectrum coincides with some of the wavelength of the upper emission wavelengths.
