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Fittoniya [83]
3 years ago
6

Sara and Sam went for a two-hour drive. According to the graph, between .75 hours and 1.25 hours into their trip, they

Physics
2 answers:
Flura [38]3 years ago
6 0

The answer is C on USAtest prep I had this question.

Free_Kalibri [48]3 years ago
4 0
I have attached a screenshot with the complete question.

Answer:
were not moving since there was no change in position

Explanation:
In the given graph, we have the x-axis showing the time they walked and the y-axis showing the distance they moved.

In the interval between 0.75 hours and 1.25 hours, we can note that the distance is remaining constant at 30 km.

This means that during this interval, their distance did not change which implies that they were not walking.

Hope this helps :)

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ankoles [38]

Answer:

model lol

Explanation:

7 0
3 years ago
Distance versus Displacement Worksheet
Umnica [9.8K]

when we find the distance we will add all the blocks so

distance = 6+6+4

distance = 14blocks

when we find the displacement we will add and minus too

As you can read he goes to the south 6 and to north 6 so he leave that place and back to the place again so the displacement is 0. and again he goes to the west 4 blocks so the displacement = <em><u>4blocks</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>west</u></em>

6 0
4 years ago
Read 2 more answers
How many joules of work are done on a box when a force of 25 N pushes it 3 m?
Anika [276]

Answer:

75joules

Explanation:

Workdone = force x distance

workdone = 25 x 3

workdone = 75joules

7 0
3 years ago
2.
krek1111 [17]

Answer:

c

Explanation:

a vector quantity has both magnitude and direction

6 0
3 years ago
A bowling ball (mass = 7.2 kg, radius = 0.11 m) and a billiard ball (mass = 0.38 kg, radius = 0.028 m) may each be treated as un
Semenov [28]

Answer:

Explanation:

Given that

Mass of bowling ball M1=7.2kg

The radius of bowling ball r1=0.11m

Mass of billiard ball M2=0.38kg

The radius of the Billiard ball r2=0.028m

Gravitational constant

G=6.67×10^-11Nm²/kg²

The magnitude of their distance apart is given as

r=r1+r2

r=0.028+0.11

r=0.138m

Then, gravitational force is given as

F=GM1M2/r²

F=6.67×10^-11×7.2×0.38/0.138²

F=9.58×10^-9N

The force of attraction between the two balls is

F=9.58×10^-9N

3 0
3 years ago
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