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Fittoniya [83]
3 years ago
6

Sara and Sam went for a two-hour drive. According to the graph, between .75 hours and 1.25 hours into their trip, they

Physics
2 answers:
Flura [38]3 years ago
6 0

The answer is C on USAtest prep I had this question.

Free_Kalibri [48]3 years ago
4 0
I have attached a screenshot with the complete question.

Answer:
were not moving since there was no change in position

Explanation:
In the given graph, we have the x-axis showing the time they walked and the y-axis showing the distance they moved.

In the interval between 0.75 hours and 1.25 hours, we can note that the distance is remaining constant at 30 km.

This means that during this interval, their distance did not change which implies that they were not walking.

Hope this helps :)

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Please answer my question
hram777 [196]

Answer:

Answer is (b) Mercury, venus and Mars.

7 0
3 years ago
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My mass is 65 kg and on Earth this equals a weight of 640 N, but on the moon where gravity is 1.7 m/s² my
Helen [10]

Your weight on the moon given the data from the question is 110.5 N

<h3>Definition of mass and weight </h3>

Mass is simply defined as the quantity of matter present in an object. The mass of an object is constant irrespective of the location of the object.

Weight is simply defined as the gravitational pull on an object. The weight of an object varies from place to place due to gravity.

<h3>Relationship between mass and weight </h3>

Mass and weight are related according to the following equation

Weight (W) = mass (m) × Acceleration due to gravity (g)

<h3>How to determine the weight on the moon</h3>
  • Mass (m) = 65 Kg
  • Acceleration due to gravity on the moon (g) = 1.7 m/s²
  • Weight (W) =?

W = mg

W = 65 × 1.7

W = 110.5 N

Learn more about mass and weight:

brainly.com/question/14684564

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4 0
1 year ago
How can I solve this?
inysia [295]
There is no equation here
3 0
3 years ago
A car accelerates from 13 m/s to 25 m/s in 5.0 s. assume constant acceleration. what was its acceleration?
natima [27]
<span>a = 25-13/6  = 12/6 = 2 m/s^2
Av speed: 25+13/2 = 38/2  = 19 m/sec
Dist = speed * time
19 * 6 = 114 meters</span>
8 0
3 years ago
Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d
Step2247 [10]
Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that F = k \frac{Q_1Q_2}{d^2} so if we double the charge on Q_1 and double the distance to (2d) we plug these into the equation to find

<span>F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}</span>

So we see the new force is exactly 1/2 of the old force so your answer should be \frac{1}{2}F if I can remember my physics correctly.

9 0
3 years ago
Read 2 more answers
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