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IgorLugansk [536]
4 years ago
9

A chemical engineer is developing a process for producing a new chemical. One step in the process involves allowing a solution o

f potassium hydroxide to react with a solid. Which action would most likely increase the reaction rate for this step? using larger pieces of the solid using a more concentrated potassium hydroxide solution adding water to the system
Chemistry
1 answer:
g100num [7]4 years ago
4 0

Answer:

using a more concentrated potassium hydroxide

Explanation:

<em>The option that would likely increase the rate of reaction would be to use a more concentrated potassium hydroxide.</em>

<u>The concentration of reactants is one of the factors that affect the rate of reaction. The more the concentration of the reactants, the faster the rate of reaction. </u>

Granted that there are enough of the other reactants, increasing the concentration of one of the reactants will lead to an increased rate of reaction.

Hence, using a more concentrated potassium hydroxide which happens to be one of the reactants would likely increase the rate of reaction.

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In the solubility lab, sugar was the _____________ and water was the _______________.
Rasek [7]

In a homogenous mixture, sugar was the solute and water was the solvent. Solubility is the maximum amount of a solute that dissolves in a given amount of solvent at a constant temperature. Solutes are more soluble in a given solvent at higher temperatures. Therefore, when temperature increases, the solubility of the solute also increases.

<span>Moreover, the solubility of the substance ranges from infinitely soluble such as alcohol in water, to poorly soluble like silver chloride in water and the species that dissolves, the solute, can be another liquid, gas or a solid.</span>

4 0
3 years ago
How many molecules of N2O4 are in 76.3g N2O4? The molar mass of N2O4 is 92.02 g/mol.
Murrr4er [49]

Answer:

4.99*10²³ molecules of N₂O₄ are in 76.3 g of N₂O₄

Explanation:

Avogadro's Number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.

You know that the molar mass of N₂O₄ is 92.02 g/mol, and you have 76.3 g. Then you can apply the following rule of three: 92.02 grams are present in 1 mole of the compound, 76.3 grams in how many moles are they?

amount of moles= \frac{76.3 grams*1 mole}{92.02 grams}

amount of moles= 0.83 moles

Then, you can apply another rule of three: if by definition of Avogadro's number 1 mole of the compound has 6.023*10²³ molecules, 0.83 moles of the compound, how many molecules will it have?

amount of molecules= \frac{0.83 moles*6.023*10^{23}molecules }{1 mole}

amount of molecules= 4.99*10²³

<u><em>4.99*10²³ molecules of N₂O₄ are in 76.3 g of N₂O₄</em></u>

6 0
3 years ago
The element oxygen, represented by the symbol O, is classified as
Katarina [22]
Oxygen<span> is a </span>chemical element<span> having a symbol </span>O<span> and having an </span>atomic number<span> 8.
Oxygen is a pure substance , and it is not a mixture or solution, Niether it is a compound ... Instead , it forms chemical compounds by reacting with other elements.
So , according to above explanation ,
A. A pure substance , is the correct answer.</span>
3 0
4 years ago
Read 2 more answers
Points + Brainalist
Lorico [155]

Answer:

I think A it looks to be the answer

Explanation:

sorry if wrong

4 0
2 years ago
Consider the following reactions: 1. 2 SO3(g) ⇄ 2 SO2(g) + O2(g) K 1 = 2.3 × 10-7 2. 2 NO3(g) ⇄ 2 NO2(g) + O2 (g) K 2 = 1.4× 10-
juin [17]

Answer:

K =78

Explanation:

Step 1: Data given

2SO3(g) <--> 2SO2(g) + O2(g)  kc = 2.3 x 10^-7

2NO3(g) <--> 2NO2(g) + )2(g)   kc = 1.4 x 10^-3

Step 2: Calculate K

Lets write out the two reactions in the proper order and look at how they sum together:

2 SO2(g) + O2(g)  <---> 2 SO3(g)   (1)

2NO3(g) <---> 2 NO2(g)  + O2(g)    (2)

The two reactions as now written give us the correct reactants and products on the correct sides of the reaction arrow.

Since we have O2 as both a reactant and a product, we can cancel O2 and are not part of the final overall reaction equation.

Koverall =  Kc1  * Kc2

Because we reversed reaction number 1 this affects its Kc via the following:

Krev  =  1/Kfwd.  

We then replace Kc1 with its value for the reverse direction.

So  Koverall now =   (1/Kfwd) * Kc2

The sum of the two reactions above gives us:

2 SO2(g) +  2 NO3(g)  <--->  2 SO3(g)  + 2 NO(g)  

The problem states to give the K value for the reaction where all the numbers in front of the molecules are (1), and we have (2)'s.  So basically  if we multiply the whole reaction by 1/2 we'll get the final overall equation we want.

1/2  ( 2 SO2(g)  + 2 NO3(g)  <----> 2 SO3(g)  + 2 NO(g) )

 

So Kfinal =  (Koverall)^1/2    

K =  ( 1/Kfwd  *  Kc2)^1/2

K =  ( [1 / 2.3 * 10^-7]   *  1.4 * 10^-3)^1/2

K =78

3 0
3 years ago
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