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IgorLugansk [536]
3 years ago
9

A chemical engineer is developing a process for producing a new chemical. One step in the process involves allowing a solution o

f potassium hydroxide to react with a solid. Which action would most likely increase the reaction rate for this step? using larger pieces of the solid using a more concentrated potassium hydroxide solution adding water to the system
Chemistry
1 answer:
g100num [7]3 years ago
4 0

Answer:

using a more concentrated potassium hydroxide

Explanation:

<em>The option that would likely increase the rate of reaction would be to use a more concentrated potassium hydroxide.</em>

<u>The concentration of reactants is one of the factors that affect the rate of reaction. The more the concentration of the reactants, the faster the rate of reaction. </u>

Granted that there are enough of the other reactants, increasing the concentration of one of the reactants will lead to an increased rate of reaction.

Hence, using a more concentrated potassium hydroxide which happens to be one of the reactants would likely increase the rate of reaction.

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Provide only the major alkene product that results when n,n-dimethylhexan-2-amine undergoes cope elimination?
Fofino [41]

The major alkene  product that results when n,n-dimethylhexan-2-amine undergoes cope elimination is hexene or hex-1-ene.

The reaction in which an amine is oxidize to an intermediate called an N-oxide which , when heated , acts as base in an intramolecular elimination reaction. The oxidation of tertiary amine into N-oxide is called cope reaction.

This elimination gives the less substituted alkene along with more substituted alkene which is Zaitsev product.

Example: Cope elimination of  n,n-dimethylhexan-2-amine form hexene.

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5 0
2 years ago
Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
How many moles are in 2.0 grams of Na?
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Answer:

46

Explanation:

Sodium metal has a molar mass of  

22.99

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Answer:

The advantages of using an indicator to inform pH measurements:

It gives a mathematically result of the pH, in addition, it gives the precise pH of solvent, and it also gives an idea of the straight of the solution also.

Now, the advantage of using a pH meter:

It is a rapid method to characterize between acids, bases. However, this method does not show how strong acid or base actually are, plus it tends to gives a range of acidity or basicity not quite accurate as a result.

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3 years ago
Calculate the molality and van’t Hoff factor (i) for the following aqueous solutions:
MissTica

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<h3>What is the value of Van t Hoff factor?</h3>

For most non-electrolytes dissolved in water, the Van 't Hoff factor is essentially $ 1 $ . For most ionic compounds dissolved in water, the Van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

<h3>Which has highest Van t Hoff factor?</h3>

The Van't Hoff factor will be highest for

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   B. Magnesium chloride.

   C. Sodium phosphate.

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3 0
1 year ago
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