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Triss [41]
2 years ago
8

Calcium carbonate (caco3) is an important component of coral reefs. how many moles are in 98.6 g of caco3? type in your answer u

sing the correct number of significant figures. 98.6 g caco3 = mol caco3
Chemistry
1 answer:
vovangra [49]2 years ago
7 0

0.986 moles of CaO are formed when  98.60 g of CaCO_3decomposes.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 ×10^{23} of some chemical unit, be it atoms, molecules, ions, or others.

Number of moles of CaCO3 =\frac{mass}{molar \;mass}

Number of moles of CaCO3 = \frac{98.60 g}{100 g/mol}

= 0.986 moles

Reaction:

CaCO_3   →  CaO + CO_2

Since the reaction is 1:1:1.

So 0.986 moles of CaO are formed.

Learn more about moles here:

brainly.com/question/26416088

#SPJ1

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Answer:

There was 450.068g of water in the pot.

Explanation:

Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L

Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s

Let m = x g be the weight of water in the pot.

Energy required to vaporise water = mL = 2260x

Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x

Total energy required = 2260x+x\times2.010\times(135-100)=2260x+70.35x=2330.35x

2330.35x=1048815\\x=450.068g

Hence, there was 450.068g of water in the pot.

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Answer:

we know, at STP ( standard temperature and pressure).

we know, volume of 1 mole of gas = 22.4L

weight of 1 Litre of hydrogen gas = 0.09g

so, weight of 22.4 litres of hydrogen gas = 22.4 × 0.09 = 2.016g ≈ 2g = molecular weight of hydrogen gas.

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