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3 years ago

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Consider an embedded system which uses a battery with a 17.15-Amp-Hour capacity. What is the maximum average current draw (in mi

cro Amps to one decimal place) that your embedded processor can have if you want the battery to last 23 years without being replaced

1 answer:

Marianna [84]3 years ago

7 0

Answer:

<em>85.12 μAmp</em>

<em></em>

Explanation:

The battery power output = 17.15 Amp-hr

If the battery is to last 23 years, we have to calculate how many hours there are in 23 years

in one year there are 24 hours x 365 day = 8760 hrs

in 23 years there are 23 x 8760 = 201480 hours

maximum current to be drawn from the battery = (17.15 Amp-hr) ÷ (201480 hours) = 85.12 x 10^-6 Amp = <em>85.12 μA</em>

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When atoms are split, they release energy. This concept applies to (2 points)

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This applies to nuclear reactions, specifically nuclear fission.

This huge release of energy has been used in atomic bombs and in the nuclear reactors that generate electricity.

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6 0

3 years ago

A ball with an initial velocity of 8.00 m/s rolls up a hill without slipping. (a) Treating the ball as a spherical shell, calcul

GrogVix [38]

Answer:

Part i)

h = 5.44 m

Part ii)

h = 3.16 m

Explanation:

Part i)

Since the ball is rolling so its total kinetic energy in this case will convert into gravitational potential energy

So we have

$\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = mgh$

here we know that for spherical shell and pure rolling conditions

$v = R \omega$

$I = \frac{2}{3}mR^2$

$\frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{3}mR^2)(\frac{v^2}{R^2}) = mgh$

$\frac{5}{6}mv^2 = mgh$

$h = \frac{5v^2}{6g}$

$h = \frac{5(8^2)}{6(9.81)} = 5.44 m$

Part b)

If ball is not rolling and just sliding over the hill then in that case

$\frac{1}{2}mv^2 = mgh$

$h = \frac{v^2}{2g}$

$h = \frac{8^2}{2(9.81)} = 3.16 m$

3 0

3 years ago

Dr. Wolski does research on the potential relationship between neurotransmitter deficiencies and mood states. Which psychologica

kipiarov [429]

Answer:

Bio psychology

Explanation:

Since, Dr. Wolski does research on the potential relationship between neurotransmitter deficiencies and mood states. His psychological specialty must be biological psychology.

Biological psychology, or bio psychology, is a discipline in which scientific investigation and clinical practice investigates the relation between brain and body. In this area scholars evaluate the biological basis of feelings, impulses and behaviors.

8 0

4 years ago

A pair of adult nitwits sit balanced on a teeter totter type device. One of them, whose mass is 54.2 kg, is 1.20 m from the poin

andreev551 [17]

Answer:

The mass of the second person is 28.91 kg

Explanation:

Given;

mass of the first adult, m₁ = 54.2 kg

distance of the first adult from the point of balance, x = 1.20 m

mass of the second adult, = m₂

distance of the second adult from the point of balance, y = 2.25 m

Taking moment about the point of balance, we will have

m₁x = m₂y

54.2 x 1.2 = 2.25y

2.25y = 65.04

y = 65.04/2.25

y = 28.91 kg

Therefore, the mass of the second person is 28.91 kg

3 0

4 years ago

Read 2 more answers

What is the velocity of an electron that has a de Broglie wavelength approximately the length of a chemical bond? Assume this le

melomori [17]

Answer : The velocity of an electron is, $6.1\times 10^{6}m/s$

Explanation :

According to de-Broglie, the expression for wavelength is,

$\lambda=\frac{h}{p}$

and,

$p=mv$

where,

p = momentum, m = mass, v = velocity

So, the formula will be:

$\lambda=\frac{h}{mv}$ .............(1)

where,

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength = $1.2\times 10^{-10}m$

m = mass of electron = $9.11\times 10^{-31}kg$

v = velocity of electron = ?

Now put all the given values in formula 1, we get:

$1.2\times 10^{-10}m=\frac{6.626\times 10^{-34}Js}{(9.11\times 10^{-31}kg)\times v}$

$v=6.1\times 10^{6}m/s$

Thus, the velocity of an electron is, $6.1\times 10^{6}m/s$

6 0

3 years ago