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Ainat [17]
2 years ago
14

What can be described as a technology that uses high-frequency sound waves to create images?

Physics
1 answer:
valkas [14]2 years ago
7 0

Answer:

Ultrasound imaging (sonography) uses high-frequency sound waves to view inside the body.

Explanation:

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A driver notices an upcoming speed limit change from 45 mi/h (20 m/s) to 25 mi/h (11 m/s). If she estimates
zloy xaker [14]

Answer:

-2.79 m/s²

Explanation:

Given:

v₀ = 20 m/s

v = 11 m/s

Δx = 50 m

Find: a

v² = v₀² + 2aΔx

(11 m/s)² = (20 m/s)² + 2a (50 m)

a = -2.79 m/s²

Round as needed.

8 0
4 years ago
Jason uses a lens with focal length of 10.0 cm as a magnifier by holding it right up to his eye. he is observing an object that
Svetlanka [38]

Answer:

3.5

Explanation:

The angular magnification, M = 1 + 25cm/f  where f = focal length = 10.0 cm

M = 1 + 25cm/f

= 1 + 25cm/10.0 cm

= 1 + 2.5

= 3.5

7 0
4 years ago
During a race, a dragster is 200m from the finish line when something goes wrong and it stops accelerating. It travels at a cons
GarryVolchara [31]

Answer:

135 m

Explanation:

Speed = 45 m/s, time = 3 second

The formula for the distance is given by

Distance = speed x time = 45 x 3 = 135 m

4 0
3 years ago
A diver who weighs 500 N steps off a diving board that is 10 m above the water. The diver hits the water with kinetic energy of_
Ksju [112]

Answer:

Diver hits the water with kinetic energy of 5000 J

Explanation:

We have given weight of the diver F = 500 N

Diver steps off a diving board which is 10 m above the water

So work don by diver W=force\times distance=500\times 10=5000J

Now according to energy theorem work done is equal to kinetic energy

So kinetic energy will be equal to 5000 J

So diver hits the water with kinetic energy of 5000 J

6 0
3 years ago
A motoris st enters a freeway at a speed of 35 mi/h and accelerates uniformly to a speed of 55 mi h. The motorist travels 500 ft
Ne4ueva [31]

Answer:

1)  The acceleration of the car = 1.17 m/s²

2) The time required to reach 55 mi/h = 7.59 seconds.

Explanation:

1)  Initial speed of motorist, u = 35 mph = 15.56 m/s

   Final speed of motorist, v = 55 mph = 24.44 m/s

   Distance traveled, s = 500ft = 152.4 m

   We have v² = u² + 2as

                  24.44² = 15.56² + 2 x a x 152.4

                  a = 1.17 m/s²

  The acceleration of the car = 1.17 m/s²  

2) We have v = u + at

                   24.44 = 15.56 + 1.17 x t

                           t = 7.59 s

   The time required to reach 55 mi/h = 7.59 seconds.  

8 0
3 years ago
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