Answer:
-2.79 m/s²
Explanation:
Given:
v₀ = 20 m/s
v = 11 m/s
Δx = 50 m
Find: a
v² = v₀² + 2aΔx
(11 m/s)² = (20 m/s)² + 2a (50 m)
a = -2.79 m/s²
Round as needed.
Answer:
3.5
Explanation:
The angular magnification, M = 1 + 25cm/f where f = focal length = 10.0 cm
M = 1 + 25cm/f
= 1 + 25cm/10.0 cm
= 1 + 2.5
= 3.5
Answer:
135 m
Explanation:
Speed = 45 m/s, time = 3 second
The formula for the distance is given by
Distance = speed x time = 45 x 3 = 135 m
Answer:
Diver hits the water with kinetic energy of 5000 J
Explanation:
We have given weight of the diver F = 500 N
Diver steps off a diving board which is 10 m above the water
So work don by diver 
Now according to energy theorem work done is equal to kinetic energy
So kinetic energy will be equal to 5000 J
So diver hits the water with kinetic energy of 5000 J
Answer:
1) The acceleration of the car = 1.17 m/s²
2) The time required to reach 55 mi/h = 7.59 seconds.
Explanation:
1) Initial speed of motorist, u = 35 mph = 15.56 m/s
Final speed of motorist, v = 55 mph = 24.44 m/s
Distance traveled, s = 500ft = 152.4 m
We have v² = u² + 2as
24.44² = 15.56² + 2 x a x 152.4
a = 1.17 m/s²
The acceleration of the car = 1.17 m/s²
2) We have v = u + at
24.44 = 15.56 + 1.17 x t
t = 7.59 s
The time required to reach 55 mi/h = 7.59 seconds.