4 years ago

A driver notices an upcoming speed limit change from 45 mi/h (20 m/s) to 25 mi/h (11 m/s). If she estimates

Physics

1 answer:

zloy xaker [14]4 years ago

8 0

Answer:

-2.79 m/s²

Explanation:

Given:

v₀ = 20 m/s

v = 11 m/s

Δx = 50 m

Find: a

v² = v₀² + 2aΔx

(11 m/s)² = (20 m/s)² + 2a (50 m)

a = -2.79 m/s²

Round as needed.

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Answer:

330.4 N and $95.2^{\circ}$ counterclocwise to the x direction

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Sum of forces in vertical are equal, let movement to right and upwards be positive while left and downwards be negative

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Resultant force= $\sqrt {(-30)^{2}+329^{2}}=330.3649497 N\approx 330.4 N$

Direction= $tan^{-1}\frac {329}{-30}=-84.78986932\approx -84.8^{\circ}$

180-84.8=95.2

Therefore, direction is $95.2^{\circ}$ counterclocwise to the x direction

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Two point charges are separated by 6 cm. The attractive force between them is 20 N. Find the force between them when they are se

Scorpion4ik [409]

Answer:

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