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dedylja [7]
3 years ago
10

The best tool to use in the school science lab to see the cells in

Chemistry
1 answer:
My name is Ann [436]3 years ago
7 0
C. electron microscope
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Why is it important that scientific knowledge changes?
aleksandrvk [35]

Answer:Scientific knowledge can change because it is often examined and re-examined by new investigations and scientific argumentation. Because of these frequent examinations, scientific knowledge becomes stronger, leading to its durability. ... B: Scientific knowledge is durable and robust, but open to change.

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4 years ago
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Defintion of isometry
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<span>A transformation that is invariant with respect to distance. That is, the distance between any two points in the pre-image must be the same as the distance between the images of the two points.</span>
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3 years ago
What is the density of 1.00 mol of carbon monoxide gas at STP?
Ksju [112]

Answer:

Density = mass / volume.

If this is an ideal gas then 1mol will take up 22.4L of volume (fact about ideal gases you should remember)

Since you have 1mol then you know the volume of the gas that you have (22.4L)

Now, just convert 1mol of CO to grams.The ptable tells you that the mass of 1 mol of C is 12g and the mass of 1 mol of O is 16g. So the mass of 1 mol of CO is......... :):)

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6 0
3 years ago
What is the standard notation for 7.934 x 10-4 ?
maks197457 [2]

Answer:

It is

Explanation:

75.34 Im hopeing this correct.Very sorry if wrong.

4 0
3 years ago
The standard enthalpy of combustion of naphthalene is –5157 kj mol-1. calculate its standard enthalpy of formation. (use data in
Artemon [7]

The combustion of naphthalene is given as:

C10H8 (s) + 12 O2 (g) --> 10CO2 (g) + 4 H2O (l)

Enthalpy of combustion ΔH = -5157 kJ/mol

Now, the enthalpy change of a reaction is given

ΔH = ∑nΔHf (products) - ∑nΔHf (reactants)

where n = number of moles

            ΔHf = enthalpy of formation

Therefore,

ΔH = [10*ΔHf(CO2) + 4*ΔHf(H2O)] - [1*ΔHf(C10H8) + 12*O2]

-5157 = [10*(-393.5) + 4*(285.83)] - [ΔHf(C10H8) + 12*(0)]

ΔHf(C10H8) = 78.68 kJ/mol

4 0
4 years ago
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