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3 years ago

An ionic compound has a generic formula of QR2.

Chemistry

1 answer:

Nina [5.8K]3 years ago

8 0

Answer:

Q= Magnesium R= Chlorine

Explanation:

The element Q should be magnesium and R is chlorine.

An ionic compound is a compound that is formed by the combination of a metal and non-metal. Such bonds forms when there is a transfer of electrons from the metals to the non-metals. This leaves a net positive charge on the metal and a negative charge on the non-metal.

The electrostatic attraction leads to the formation of the bond.

To solve this problem, the hypothetical compound is QR₂

Mg Cl

2 8 2 2 8 7

So, Mg transfers 2 electrons to two atoms of chlorine.

This leads to the formation of the compound MgCl₂

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A student needs exactly 1 gram of baking powder to conduct an experiment. The balance reads 0.37 grams. How

sammy [17]

Answer:

Explanation:

If the student needs one gram but so far only has 0.37 grams, then the amount they need is the difference between what they need and how much they already have. 1-0.37=0.63 grams.

...which isn't actually an option because none of them have decimal points but I would say it is B anyway because it is the equivalent ratio and maybe there was a typo.

Hope this helped!

6 0

3 years ago

Read 2 more answers

Explain Charles law

kodGreya [7K]

"Charles Law" is the relationship between "volume-temperature" (V ∝ T).

<u>Explanation</u>:

Charles Law is basically volume-temperature relationship (V ∝ T). French scientist “Jacques Charles” in 1787 studied effect of temperature on the volume of gases at constant pressure, which described how gases manage to expand when heated. Law stated as “At constant pressure, the volume of a given "mass" of a gas decreases or increases by 1/273 of its volume at $0^{\circ} \mathrm{C}$ for each one degree rise or fall in temperature”. Formula derived from law is as follows: $\mathbf{V}_{\mathbf{t}}=\mathbf{V}_{0}[\mathbf{1}+\mathbf{t} / \mathbf{2} 7 \mathbf{3}]$ here ${V}_{0}$ is volume of given mass of a gas at $0^{\circ} \mathrm{C}$ , ${V}_{t}$ is its volume at any temperature $t^{\circ} \mathrm{C}$ . Application of Charles law is hot air balloons.

8 0

2 years ago

9.69 × 10^7 in decimal form

iren [92.7K]

The answer is 96,900,000

4 0

2 years ago

Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse

amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

6 0

3 years ago

Read 2 more answers

. What is the first element on the periodic table?

melamori03 [73]

Answer:

The first element in the periodic table is hydrogen.

Explanation:

Hydrogen has an atomic number of one, making it the first element of the periodic table. The atomic number of an element is just the number of protons in the nucleus, so hydrogen has one proton. The neutrons and electrons do not affect the atomic number. After hydrogen with one proton comes helium with two, lithium with three, beryllium with four, and so on.

6 0

3 years ago