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3 years ago

An ionic compound has a generic formula of QR2.

Chemistry

1 answer:

Nina [5.8K]3 years ago

8 0

Answer:

Q= Magnesium R= Chlorine

Explanation:

The element Q should be magnesium and R is chlorine.

An ionic compound is a compound that is formed by the combination of a metal and non-metal. Such bonds forms when there is a transfer of electrons from the metals to the non-metals. This leaves a net positive charge on the metal and a negative charge on the non-metal.

The electrostatic attraction leads to the formation of the bond.

To solve this problem, the hypothetical compound is QR₂

Mg Cl

2 8 2 2 8 7

So, Mg transfers 2 electrons to two atoms of chlorine.

This leads to the formation of the compound MgCl₂

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The value of the equilibrium constant for a reaction is 2.65 x 10-6 at 35° Calculate the value of LaTeX: \DeltaΔG°rxn.

stealth61 [152]

Answer:

The answer is "33.95 $\bold{ \frac{kj}{mol}}\\$ ".

Explanation:

Formula:

$\bigtriangleup G_0= -R \times T l_n \times K_{eq}\\$

where

$K_{eq} = \text{equilibrium constant}\\$

Given value:

$T =35^{\circ} C\\$

convert temperature celsius (°C) to Kelvin (K):

$= (273+45) \ kelvin \\\\= 318 \ Kelvin \\\\= 318 \ K$

$R = 8.314 \ \ \frac{J}{ mol \cdot K}$

$\bigtriangleup G_0= -(8.314 ) \times 31.8 \times l_n (2.65\times 10^{-6})\\$

$=-(8.314 ) \times 31.8T l_n \times (2.65\times 10^{-6})\\\\$

After solving the value it will give:

= 33.95 $\bold{ \frac{kj}{mol}}\\$

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What is the amplitude of the wave above? *

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The correct answer is 15

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What is the total number of electrons in all s orbitals of a neutral atom of phosphorus?

kenny6666 [7]

In order to find out the number of electrons present in s orbital of Phosphorous we have to write the electronic configuration of phosphorous.

As the Atomic number of Phosphorous is 15 so it will have 15 electrons in neutral state. So,

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Now analyzing electronic configuration, we found that it contains 3 s orbitals, i.e. 1s, 2s and 3s, and each s orbital is completely filled with two electrons each.

Result:
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