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salantis [7]
3 years ago
10

The figure shows two forces acting on an object, with magnitudes F1 = 78 N and F2 = 26 N.

Physics
2 answers:
Stels [109]3 years ago
8 0
A 52 N is your answer
Alecsey [184]3 years ago
5 0
A - 52N pointing down
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a horizontal clothesline is tied between 2 poles, 10 meters apart. when a mass of 1 kilograms is tied to the middle of the cloth
natali 33 [55]

By analyzing the vector, the clothesline tension is 25 N.

We need to know about vectors to solve this problem. Force is included in vectors that have magnitude and direction. It can be written as

F = (Fx i + Fy j) N

where F is the force vector, Fx is the x-axis component and Fy is the y-axis component.

From the question we know that :

x = 10 m

(midpoint = 5m)

y = 1 m

m = 1 kg

Find the weight

W = m . g

W = 1 x 10

W = 10N

There are two y-axis components of the tension that hold the clothes. Because of static conditions, we can write

∑Fy = 0

Ty + Ty - W = 0

2Ty - 10 = 0

2Tsinθ - 10 = 0

Find sinθ

sinθ = y/x

sinθ = 1/5

Substitute the sinθ

2Tsinθ - 10 = 0

2T(1/5) - 10 = 0

2T/5 = 10

T = 25 N

Hence, the clothesline tension is 25 N.

For more about vectors at: brainly.com/question/25811261

#SPJ4

6 0
1 year ago
A worker pushes a crate horizontally across a warehouse floor with a force of 245 N at an angle of 55 degrees below the horizont
aev [14]

Answer:

option A

Explanation:

given,

For exerted by the worker = 245 N

angle made with horizontal = 55°

we need to calculate Force which is not used to move the crate = ?

Movement of crate is due to the horizontal component of the force.

Crate will not move due to vertical force acting on the it.

F_y = F sin \theta

F_y = 245\times sin 55^0

F_y =200.69

hence, worker's force not used to move the crate is equal to 200.69

The correct answer is option A

6 0
3 years ago
Read 2 more answers
True or False: A higher vapor pressure (evaporates easily) corresponds to strong intermolecular forces. (dont answer)
HACTEHA [7]

Answer:

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6 0
3 years ago
Read 2 more answers
A bottle of water at a room temperature of 21.0 C is placed into a refrigerator
fredd [130]

Answer:

B. in both directions until the temperature is equal in the water and the air

Explanation:

When a warm body is in contact with a cool body , there is exchange of heat energy in both sides until there is attainment of equilibrium temperature . At this temperature both the body attains equal temperature . Initially rate of heat radiated by warm body is more than that from cool body , but after attainment of equilibrium , the rate becomes equal to each other . This is called dynamic equilibrium .

Hence option B is correct .

7 0
3 years ago
Infrared radiation has frequencies from 3.0×1011 to 3.0×1014 Hz, whereas the frequency region for microwave radiation is 3.0×108
igor_vitrenko [27]

Answer:

1. The speed of infrared radiation is the same as microwave radiation.

2. The wavelength of infrared radiation is lower than microwave radiation.

Explanation:

1. The speed of infrared radiation is the same as microwave radiation. This is because both infrared radiation and microwave radiation are electromagnetic waves and all electromagnetic waves move at the same speed, the speed of light.

2. Frequency and wavelength has an inverse relationship. This means that the higher the frequency, the lower the wavelength.

Since the frequency range of infrared waves is higher than that of microwaves, the wavelength range of infrared waves is lower than that of microwaves.

We can prove this by using the maximum frequency value of each wave to calculate their corresponding wavelengths.

Speed of light, c, is given as:

c = λf

Where λ is wavelength and f is frequency.

Wavelength is therefore:

λ = c/f

For infrared wave, the maximum frequency is 3 * 10^14 Hz, hence the corresponding wavelength is:

λ = (3 * 10^8) / (3 * 10^14)

λ = 10^(-6) m

For microwave, the maximum frequency is 3 * 10^11 Hz, hence the corresponding wavelength is:

λ = (3 * 10^8) / (3 * 10^11)

λ = 10^(-3) m

Hence, the wavelength of infrared waves is lower than the wavelength of microwaves.

8 0
3 years ago
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