Answer and Explanation:
As per the question:
When the stone is thrown from the cliff top and hits the ground below eventually:
R = 
where
= initial velocity
H = height
g = acceleration due to gravity
R = horizontal Range
Now,
(a) Displacement of the stone is given by the horizontal range:
R =
where
= initial velocity
H = height
g = acceleration due to gravity
R = horizontal Range
(b) Speed just prior to the impact is given by the third equation of motion:
where
v = final velocity
(c) Time of flight is given by the second eqn of motion where the initial velocity is considered to be 0 then:
T = 
From a to b speed is 600+40 = 640
from b to a speed is 600-40 = 560
let t be the number of hours of flight. This would mean it would have traveled a distance of 640 miles and the distance yet to travel is 2400-640t
Time left will be (2400-640t)/640. But if they were to return to a it would fly 640t miles at 560mph which will take (640t/560) hrs
(2400-640t) / 640 = 640t / 560
560(2400 - 640t) = 640t x 640
t = 1.75hrs
Answer:
The correct answer is b. Differences in Path Lenght
Explanation:
In this area of knowledge, there two main ways of referring to Path Lenght:
1. The total distance an object travels from a starting point, without considering trajectory.
2. When talking about wavelength, because this relates to light and how it travels throughout different mediums. This concept is used in calculating constructive and destructive interference of waves, and is responsible for seeing different shades of tea color.
Hope this helps!
Answer:
First choice
Explanation:
A satellite in orbit around Earth experiences only one force: the gravitational attraction exerted by the Earth on it. This force is labelled with 
. In space, there are no other forces acting on the satellite.
The force of gravity acts as centripetal force, "pulling" the satellite towards the centre of its circular orbit. The inertia of the satellite (which has an initial velocity) tends to keep it moving straight, so the combination of these two effects (inertia and force of gravity) results into the circular motion of the satellite.
