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chubhunter [2.5K]
3 years ago
13

A scientist needs to collect a 0.050 mole sample of helium, but needs to know how large his helium container should be. What vol

ume is needed to store the sample of helium gas at 202.6kPa and 400K? A. 657 milliliters B. 760 milliliters C. 820 milliliters D. 1,025 milliliters
Chemistry
1 answer:
Mumz [18]3 years ago
8 0

We can use the ideal gas equation:

PV = nRT

P = 202.6kPa = 202600 Pa (You have to multiply by 1000)

n = 0.050 mole

R = 0.082 atm*l/(K*mol)

T = 400K

We will have to convert from Pa to atm or viceversa.

101325 Pa________1 atm

202600 Pa________x = 2.00 atm

2atm*V = 0.050 mole*0.082 atm*l/(K*mol)* 400K

V = 0.050 mole*0.082 atm*l/(K*mol)* 400K/2atm = 0.82 liters = 820 mililiters



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Circle only those of the following reactions that are redox reactions:
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Answer: options B,D and F

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In B , Cu is oxidized and S gets reduced

D, Na gets oxidized and hydrogen gets reduced

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If a radiation source has a wavelength of 4.76 x 10-6 m, then what is its frequency?
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The answer is: volume of nitrogen is 70L.

Chemical reaction: N₂H₄ + O₂ → N₂ + 2H₂O.

m(N₂H₄) = 100 g; mass of hydrazine.

M(N₂H₄) = 32 g/mol; molar mass of hydrazine.

n(N₂H₄) = m(N₂H₄) ÷ M(N₂H₄).

n(N₂H₄) = 100 g ÷ 32 g/mol.

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m(O₂) = 100 g; mass of oxygen.

M(O₂) = 32 g/mol; molar mass of oxygen.

n(O₂) = 100 g ÷ 32 g/mol.

n(O₂) = 3.125 mol; amount of oxygen.

From chemical reaction: n(O₂) : n(N₂) = 1 : 1; n(O₂) = n(N₂).

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V(N₂) = 3.125 mol · 22.4 L/mol.

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There is not excess reagent, because hydrazine and oxygen are all used in chemical reaction.

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