A scientist needs to collect a 0.050 mole sample of helium, but needs to know how large his helium container should be. What vol ume is needed to store the sample of helium gas at 202.6kPa and 400K? A. 657 milliliters B. 760 milliliters C. 820 milliliters D. 1,025 milliliters
1 answer:
We can use the ideal gas equation:
PV = nRT
P = 202.6kPa = 202600 Pa (You have to
multiply by 1000)
n = 0.050 mole
R = 0.082 atm*l/(K*mol)
T = 400K
We will have to convert from Pa to atm or
viceversa.
101325 Pa________1 atm
202600 Pa________x = 2.00 atm
2atm*V = 0.050 mole*0.082 atm*l/(K*mol)* 400K
V = 0.050 mole*0.082 atm*l/(K*mol)* 400K/2atm
= 0.82 liters = 820 mililiters
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