Answer:
(A) -2940 J
(B) 392 J
(C) 212.33 N
Explanation:
mass of bear (m) = 25 kg
height of the pole (h) = 12 m
speed (v) = 5.6 m/s
acceleration due to gravity (g) = 9.8 m/s
(A) change in gravitational potential energy (ΔU) = mg(height at the bottom- height at the top)
height at the bottom = 0
= 25 x 9.8 x (0-12) = -2940 J
(B) kinetic energy of the Bear (KE) =
= = 392 J
(C) average frictional force =
- change in KE (ΔKE) = initial KE - final KE
- ΔKE = -
- when the Bear reaches the bottom of the pole, the final velocity (Vf) is 0, therefore the change in kinetic energy becomes ΔKE = - 0 = 392 J
\frac{-(ΔKE+ΔU)}{h}[/tex] =
= = 212.33 N
Answer:
let current flow be x
Explanation:
than we know potential difference = energy supply / charge then 120 = 10 /x then x=12 therefore pd = 12 v
Yes they do. So if you need to add or subtract a pair, then you have to first change one or the other so that they both have the same power of 10.
Http://www.kyrene.org/cms/lib2/AZ01001083/Centricity/Domain/2932/Peppered%20Moth%20and%20Galapados%20Island%20PowerPoint.pptx
This should lead you to correct answer
Answer:
volume : {l}^3
speed: (l)^1*(t)^-1
Explanation:
Volume is a measure of 3 dimensional space. It is expressed with 3 orthogonal lengths. The volume of a box would be the product of it's height, width and length. These 3 are longitudes that can be expressed in meters, feet, inches, etc. Because these are 3 longitudes multiplied the result will be a cubic longitude (l)^3.
A more general method for finding a volume is to use integral calculus:
This is for Cartesian coordinates. Cylindrical and spherical coordinates can also be used.
Speed is defined as the rate of change in position respect of time:
For movement in one dimension.
For movement in 3 dimensions you calculate the speed component of each space direction and express them as components of a speed vector:
This is a vector of velocity components, each one is expressed as a division of a longitude over a time, so speed components have dimensions of (l)^1*(t)^-1
The speed vector has a magnitude that is obtained with the Pitagoras theorem:
Since each component is squared, added together and then the square root is taken this magnitude is also in (l)^1*(t)^-1