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2 years ago

Help me with the following problem

Physics

1 answer:

xxMikexx [17]2 years ago

5 0

The mass of 1 mole of iron is 0.056 kg/mol; molar density of iron is 139285.71 mol/m³; number density of iron is 4.33 * 10¹⁸ atom/m³; number density of conduction electrons is 8.66 * 10¹⁸ electrons/m³; drift velocity of electrons, v is 6.2 * 10⁶ m/s.

The mass of 1 mole of iron is 56 g/mol

Mass in kg/mol = 56 gmol * 1 kg/1000 g

Mass in kg/mol = 0.056 kg/mol

Molar density of iron = density of iron/molar mass of iron

Density of iron = 7800 kg/m³

Molar density of iron = 7800 kg/m³ / 0.056 kg/mol

Molar density of iron = 139285.71 mol/m³

Number density of iron = (6.02 * 10²³ atom/mol)/(139285.71 mol/m³)

Number density of iron = 4.33 * 10¹⁸ atom/m³

Number density of conduction electrons = 4.33 * 10¹⁸ atom/m³ * 2 electrons/atom

Number density of conduction electrons = 8.66 * 10¹⁸ electrons/m³

Drift velocity of electrons, v = I/nAQ

Where,

I is the current flowing through the conductor

n is the number of electrons

A is the area of the cross-section of the conductor in m²

v is the drift velocity of the electrons

Q is the charge of an electron = 1.6 × 10⁻¹⁹ Coulombs

Drift velocity of electrons, v = 31.0/(8.66 * 10¹⁸ * 3.6 * 10⁻⁶ * 1.6 × 10⁻¹⁹ )

Drift velocity of electrons, v = 6.2 * 10⁶ m/s

Therefore, the mass of 1 mole of iron is 0.056 kg/mol; molar density of iron is 139285.71 mol/m³; number density of iron is 4.33 * 10¹⁸ atom/m³; number density of conduction electrons is 8.66 * 10¹⁸ electrons/m³; Drift velocity of electrons, v is 6.2 * 10⁶ m/s.

Learn more about drift velocity of electrons at: brainly.com/question/22406248

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The deceleration, "a" of the truck is given by the following kinematic equation of motion

v = u - a·t

Where;

v = The final velocity of the truck = 0 m/s

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