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wolverine [178]
4 years ago
8

Definition of synthesis

Physics
1 answer:
Finger [1]4 years ago
6 0
Combination or composition, in particular.
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One out of every 92 tax returns that a tax auditor examines requires an audit. If 50
user100 [1]

Answer:

<h2>I think it's </h2>

<h2>0.8971-?? </h2>

correct me if I'm wrong because thats what my note said

3 0
3 years ago
Can any one please help me with this one really need help
gulaghasi [49]
A compression is where the particles in the air are closer together, so where those black lines are closer together.
A rarefaction is the opposite, where they're spread out.

The wavelength is the distance between two compressions or rarefactions (i.e. two peaks or troughs on a graph), therefore thats the horizontal arrows.

The amplitude is the distance from the centre of the wave to the peak or trough, so that is the vertical distance on the diagram.
8 0
4 years ago
Does the eruption in the video constitute a pyroclastic flow
densk [106]

If it is the video I am thinking of then Yes


7 0
4 years ago
Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel
andrew-mc [135]

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\Delta W), medido en joules, que reducida a:

\Delta W = m\cdot g\cdot \Delta z (1)

Donde:

m - Masa del montañero, medido en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\Delta z - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que m = 65\,kg, g = 9,807\,\frac{m}{s^{2}} y \Delta z = 500\,m, entonces el trabajo realizado por el montañero para subir es:

\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)

\Delta W = 318727,5\,J

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

7 0
3 years ago
Acceleration problem <br> Show work plz
Dennis_Churaev [7]

Answer:

The answer to your question is: vo = 25 m/s

Explanation:

data

a = -7.5 m/s²

d = 42 m

vf = 0 m/s

vo = ?

Formula

vf² = vo² - 2ad

Substitution

0² = vo² - 2(7.5)(42)

We clear vo from the equation

vo² = 2(7.5)(42)  

vo² = 630               simplifying

vo = 25 m/s            result

3 0
3 years ago
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