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3 years ago

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A damped oscillator is released from rest with an initial displacement of 10.00 cm. At the end of the first complete oscillation

, the displacement reaches 9.05 cm. When 4 more oscillations are completed, what is the displacement reached

1 answer:

Tpy6a [65]3 years ago

5 0

Answer:

The displacement is $A_r = 6.071 \ cm$

Explanation:

From the question we are told that

The initial displacement is $A_o = 10 \ cm$

The displacement at the end of first oscillation is $A_d = 9.05 \ cm$

Generally the damping constant of this damped oscillator is mathematically represented as

$\eta = \frac{A_d}{A_o}$

substituting values

$\eta = \frac{9.05}{10}$

$\eta = 0.905$

The displacement after 4 more oscillation is mathematically represented as

$A_r = \eta^4 * A_d$

substituting values

$A_r = (0.905)^4 * (9.05)$

$A_r = 6.071 \ cm$

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