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rosijanka [135]
2 years ago
12

1. Write the reaction rate expressions for the following reactions in terms of the disappearance of the reactants and the appear

ance of products: 1-(aq)+ OCI-(aq)-CI-(aq)+OI-(aq)
Chemistry
1 answer:
kirza4 [7]2 years ago
7 0

In terms of the disappearance of the reactants, the rate equations are R= -kd[I-]/dt and  -kd[OCl-]/dt.

<h3>What is an ionic reaction?</h3>

The term ionic reaction refers to the reaction that takes place between two ions. In this case, the ionic reaction is; I-(aq) + OCl-(aq) -------> Cl-(aq) + OI-(aq).

The rate equations in terms of the disappearance of the reactants is;

R= -kd[I-]/dt

And

R = -kd[OCl-]/dt

Learn more about ionic reaction:brainly.com/question/12164558

#SPJ1

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Calculate the pH and fraction of dissociation ( α ) for each of the acetic acid ( CH 3 COOH , p K a = 4.756 ) solutions. A 0.002
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Answer:

The degree of dissociation of acetic acid is 0.08448.

The pH of the solution is 3.72.

Explanation:

The pK_a=4.756

The value of the dissociation constant = K_a

pK_a=-\log[K_a]

K_a=10^{-4.756}=1.754\times 10^{-5}

Initial concentration of the acetic acid = [HAc] =c = 0.00225

Degree of dissociation = α

HAc\rightleftharpoons H^++Ac^-

Initially

c

At equilibrium ;

(c-cα)                                cα        cα

The expression of dissociation constant is given as:

K_a=\frac{[H^+][Ac^-]}{[HAc]}

1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}

1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}

1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}

Solving for α:

α = 0.08448

The degree of dissociation of acetic acid is 0.08448.

[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M

The pH of the solution ;

pH=-\log[H^+]

=-\log[0.0001901 M]=3.72

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