Answer:
We would see 5 peaks. 35Cl the lightest and 37Cl2 the heaviest
Explanation:
The chlorine element has two isotopes (35 Cl and 37 Cl), in the mass spectrum we can observe the m/e of the diatomic molecules. Formed by an atom of chlorine 35 and another of chlorine 35. Or one of Cl 35 and one of Cl 37. Or both of Cl 37.
We can also observe the mass of each separately. That is why we would see 5 peaks.
- Cl = 35 <------------------------- lightest
- Cl = 37
- Cl2 = 35 + 35 = 70
- Cl2 = 35 + 37 = 72
- Cl2 = 37 + 37 = 74 <-------- heaviest
Answer:
1.044 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is dissolved in water to a total volume of 33.0 mL, the osmotic pressure of the solution is 3.69 atm at 295 K.
Answer: Use of Etherificarion followed by fractional distinction.
Explanation:
It is done by reacting a mixture of tetrahydrofurfuryl alcohol and up to about one equivalent of at least one low work function element, Reacting the said mixture with a halide; fractionally distilling said reacted mixture to yield the first distillate; reacting said first distillate with an excess amount of at least one low work function element; and, fractionally distilling said reacted first distillate to obtain the purified ether wherein said at least one low work function element is an elemental metal or a metal hydride which has a φ of less than about 3.0 eV.
Thus, each atom or ion of sulfur must contain 16 protons. We are told that the ion also has 16 neutrons, meaning the mass number of the ion is 16 + 16 = 32. Because the ion has 16 protons and 18 electrons, its net charge is 2–. Thus, the symbol for the ion is 32S2–.