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d1i1m1o1n [39]
3 years ago
8

Vines most successfully compete for sunlight in tropical rainforests by _______.

Chemistry
1 answer:
julsineya [31]3 years ago
6 0

Answer:

climbing up into the canopy

Explanation:

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Hello there
Mumz [18]
The answer is the third one because density is mass divided by volume so 80 divided by 10 is 8
6 0
3 years ago
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A boy found a solid metal box in his backyard. The box had been buried for so long, it was difficult to determine from what the
Alex777 [14]

Answer:

Box is made up of <em>copper</em>, because density is <em>8.96  g/cm³.</em>

Explanation:

Given data:

Volume of box = 17.63 cm³

Mass of box = 158 g

Which metal box is this = ?

Solution:

First we will calculate the density of box then we will compare it with the density value of given metals.

d = m/v

d = 158 g/ 17.63 cm³

d = 8.96  g/cm³

The calculated density is similar to the given density value of copper thus box is made up of copper.

4 0
4 years ago
For each of the following sublevels, give the n and l values and the number of orbitals: (a) 5s; (b) 3p; (c) 4f
OverLord2011 [107]

Answer:

(a) 5s. n = 5. Sublevel s, l = 0. Number of orbitals = 1

(b) 3p. n = 3. Sublevel p, l = 1. Number of orbitals = 3

(c) 4f. n =4. Sublevel f, l = 3. Number of orbitals = 7

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Sublevel number, 0 ≤ l ≤ n − 1

So,

(a) 5s. n = 5, shell number 5. Sublevel s, l = 0. Number of orbitals = 2l +1 = 1

(b) 3p. n = 3, shell number 3. Sublevel p, l = 1. Number of orbitals = 2l +1 = 3

(c) 4f. n =4, shell number 4. Sublevel f, l = 3. Number of orbitals =  2l +1 = 7

6 0
3 years ago
How many atoms are there in each of the following ?a.)1.50 mol Na c.) 0.250 mol. Sib.)6.755 mol Pb
tamaranim1 [39]
a) \: n = \frac{N}{NA} \\ 1.5 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 1.5 \times 6.02 \times {10}^{23} \\ x = 9.03 \times {10}^{23} \: atoms \: of \: Na

b) \: n = \frac{N}{NA} \\ 0.25 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 0.25 \times 6.02 \times {10}^{23} \\ x = 1.505 \times {10}^{23} \: atoms \: of \: Si \:
c) \: n = \frac{N}{NA} \\ 6.755 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 6.755 \times 6.02 \times {10}^{23} \\ x = 40,6651 \times {10}^{23} \\ x = 4.07 \times {10}^{24} \: atoms \: of \: Pb \:
5 0
3 years ago
The only nonmetal in Group 14 is<br> A carbon.<br> B. oxygen.<br> C. nitrogen.<br> D. fluorine.
lesantik [10]

Answer:

carbon

Explanation:

i just googled it

4 0
3 years ago
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