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yaroslaw [1]
3 years ago
6

An object with a mass of 0.5 kilometre start from rest and achieves a maximum speed of 20 metre per second in 0.01 second, what

average unbalanced force accelerated this object
Physics
1 answer:
Katarina [22]3 years ago
3 0

Answer:

Hiii how are you <u>doing?</u><u>?</u><u>I </u><u>don't</u><u> </u><u>understand</u><u> </u><u>that</u>

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Differentiate between atmospheric pressure and pressure.​
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Answer: atmospheric is air by the earth and pressure is just someone or something doing it

Explanation:

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Which is greater - the average depth of the ocean, or the average elevation of the continents?
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The average depth of the ocean
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1200 N-m of torque is used to drive a gear (A) of diameter 25 cm, which in turn drives another gear (B) of diameter 52 cm. What
NNADVOKAT [17]

Answer:

2.5kN.m

Explanation:

Torque is directly proportional to pitch diameter

= Ta/Tb= Da/Db

=120/Tb= 0.25/0.5

Tb= 2.469kN.m approx 2.5kN.m

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In 1985, during the construction of a skyscraper in Austin, Texas, the remains of a mastodon were unearthed. If only 1/64 of the
Art [367]

Answer:

  • <u>34,380 years</u>

Explanation:

The remaining amount of a radioactive isotope is found as the product of the original amount by (1/2) raised to the number of half-lives elapsed. The formla is:

  • M = M₀ × (1/2)ⁿ

Where M is the remaining amoun, M₀ i s the initial amount, and n is the number of half-lives.

Here, 1/64 of the original carbon-14 remained, meaning that M/M₀ = 1/64.

Then, you can substitute in the equation and solve:

  • (1/64) = (1/2)ⁿ
  • (1/2⁶) = (1/2ⁿ)
  • 2⁶ = 2ⁿ
  • 6 = n

Then, 6 half-lives elapsed since the mastodon died and the remains were dated.

Then, you must multiply 6 by the <em>half-life </em>time:

  • 6 × 5730 years = 34,380 years ← answer
8 0
4 years ago
b) Assume the rod is 0.60 m long and has a mass of 0.50 kg, and the clay blob has a mass of 0.20 kg and moves at an initial velo
SOVA2 [1]

Answer:

The correct answer is "6.96 rad/s".

Explanation:

The given values are:

Length,

L = 0.6 m

Mass,

m₁ = 0.5 kg

m₂ = 0.2 kg

Initial velocity,

V = 8 m/s

Now,

The final angular velocity will be:

⇒ \omega =\frac{6m_1V}{(4m_1+3m_2)L}

By substituting the values, we get

⇒     =\frac{6\times 0.2\times 8}{(4\times 0.2+3\times 0.5)0.6}

⇒     =\frac{9.6}{1.38}

⇒     =6.96 \ rad/s

4 0
3 years ago
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