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Andrej [43]
3 years ago
14

The mass of an object is measured on Earth. The mass is 5.0kg.The object is taken to the Moon. The mass of the object is measure

d on the Moon. What is the mass of the object on the Moon?
Physics
1 answer:
BabaBlast [244]3 years ago
3 0

Answer:

Mass on the moon: 5 Kg

Explanation:

Mass will stay the same. Mass of an object does not depend on gravitational force as it is the quantity on matter possessed by a body.

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the focal length of a simple magnifier is 8.50 cmcm . assume the magnifier to be a thin lens placed very close to the eye.
Igoryamba

When the object is at the focal point the angular magnification is 2.94.

Angular magnification:

The ratio of the angle subtended at the eye by the image formed by an optical instrument to that subtended at the eye by the object when not viewed through the instrument.

Here we have to find the angular magnification when the object is at the focal point.

Focal length = 6.00 cm

Formula to calculate angular magnification:

Angular magnification = 25/f

                                            = 25/ 8.5

                                             = 2.94

Therefore the angular magnification of this thin lens is 2.94

To know more about angular magnification refer:: brainly.com/question/28325488

#SPJ4

5 0
1 year ago
The filament of a certain lamp has a resistance that increases linearly with temperature. When a constant voltage is switched on
Neporo4naja [7]

Answer:

162.8 K

Explanation:

initial current = io

final current, i = io/8

Let the potential difference is V.

coefficient of resistivity, α = 43 x 10^-3 /K

Let the resistance is R and the final resistance is Ro.

The resistance varies with temperature

R = Ro ( 1 + α ΔT)

V/i = V/io (1 + α ΔT )

8 = 1 + 43 x 10^-3 x ΔT

7 = 43 x 10^-3 x ΔT

ΔT = 162.8 K

Thus, the rise in temperature is 162.8 K.

5 0
3 years ago
Electrons are accelerated in the picture tube of a television through potential difference of 8.00 * 10 ^ 3 V. (Use the values q
maria [59]

Answer:

\lambda=1.37\times 10^{-11}\ m

Explanation:

Give that,

The potential difference of the electrons, V=8\times 10^{3}\ V

We need to find the wavelength of the electrons.

Using the conservation of energy,

2meV=\dfrac{h^2}{\lambda^2}\\\\\lambda=\sqrt{\dfrac{h^2}{2meV}}

Put all the values,

\lambda=\sqrt{\dfrac{(6.63\times 10^{-34})^2}{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 8\times 10^3}}\\\\\lambda=1.37\times 10^{-11}\ m

So, the wavelength of the electrons is 1.37\times 10^{-11}\ m.

7 0
3 years ago
A box is being pulled to the right. The free body diagram is shown.What is the magnitude of the kinetic frictional force?
kirill115 [55]

Answer:

A - 0 N

plz mark 5 stars, thanks, and brainliest

4 0
3 years ago
What is a unit for gas particle pressure? (Choose all that apply)<br> torr<br> kPa<br> mm Hg<br> atm
Pie

Answer:

pascals

Explanation:

8 0
3 years ago
Read 2 more answers
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